Answered: For the reaction Cr(C6H6)2 (s) -->…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

For the reaction Cr(C₆H₆)₂ (s) --> Cr(s) + 2 C₆H₆ (g), the reaction internal energy change at 1 atm and 538 K is DU_rxn^o(T = 538K) = 8.0 kJ/mol.

(a) Estimate the molar enthalpy of reaction at 1 atm and 538 K for the above reaction.

(b) If the standard molar enthalpy of formation for C₆H₆ at 1 atm and 538 K is about DH_f^o (C₆H₆(g)) = 84 kJ/mol, estimate the standard enthalpy of formation of Cr(C₆H₆)₂ (s) at 1 atm and 538 K.

Expert Solution

Step 1

The internal energy change can be calculated by the following formula.

$\begin{array}{rcl} ∆ H & = & ∆ U - ∆ n_{(g)} RT \\ ∆ U & = & change in internal energy \\ ∆ H & = & change in enthalpy \\ ∆ n_{(g)} & = & change in moles of gaseous atoms \\ R & = & gas constant \\ T - temperature \end{array}$

The standard enthalpy of reaction have the following formula.

$∆ {H^{0}}_{reaction} = \sum_{}^{} n ∆ {H_{f}}^{0}_{_{} products} - \sum_{}^{} n ∆ {H_{f}}^{0}_{reactants} ∆ {H_{f}}^{0}_{products} = standard molar enthalpy of formation of products ∆ {H_{f}}^{0}_{reactants} = standard molar enthalpy of formation of reactants$

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions