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a)Enter the Moment of Inertia of the rectangle (1) about its own centroidal x-axis, Enter your answer in the form: x106 mm4, to five significant figures.
b)Enter the Moment of Inertia of the rectangle (1) about the x-axis, Ix Enter your answer in the form: x106 mm4, to five significant figures.
c)Enter the Moment of Inertia of the quarter circle (2) about its own centroidal x-axis, Enter your answer in the form: x103 mm4, to five significant figures.
d)Enter the Moment of Inertia of the quarter circle (2) about the x-axis, Enter your answer in the form: x106 mm4, to five significant figures.
e)Enter the Moment of Inertia of the triangle (3) about its own centroidal x-axis, Enter your answer in the form: x103 mm4, to five significant figures.
f)Enter the Moment of Inertia of the triangle (3) about the x-axis, Enter your answer in the form: x103 mm4, to five significant figures.
g)Enter the Moment of Inertia of the Composite shape about the x-axis, Ix :Enter your answer in the form: x106 mm4, to five significant figures.
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- Determine the moment of inertia about the x-axis of the rectangular area without and with the central rectangular hole. without hole: 0.1125 b4; with hole:0.110183 b4 without hole: 0.1152 b4; with hole:0.111038 b4 without hole: 0.1215 b4; with hole:0.111083 b4 without hole: 0.1125 b4; with hole:0.110138 b4arrow_forwardMoment of Inertia Determine the moment of inertia with respect to line OA of the thin plate shown in the Figure 1. The material has a mass per unit area of p and the dimension of the plate is shown in the Table. a b C (kg/m?) (m) (m) (m) 4 4 3 1 A (0, b, c) Figure 1arrow_forwardFrom the given figure, determine the following: a. Moment of Inertia along x and y with respect to the given axis b. Moment of Inertia along x and y with respect to the centroidal axis c. Polar Moment of inertia with respect to the given axis d. Polar Moment of inertia with respect to the centroidal axisarrow_forward
- 50 mm 150 mm 150 mm 300 mm find the moment of inertia for this exercise, with the following formulas: Polar Jo= Iox + + Toy Iox - Icx + Adg² Toy = Icg + dobe ² Caculation of centroid attached below. use it to solve the question in red box asap Som Av 3com for Portion A₁ - the figure is symme about y-aris. 2=0. AL 120mm AALD Area of A₁ = 300x50 = 15000 Y₁ = y₁ y = 300 for Pation A2 Area Az = 50x300 = 15000 By Considering Centroid, from the Bottom of the section. 300+ 50 = ₁ + 3/2 = 325 Centroid (ā, y) = = [0₁ SE = 50mm A, Ya+ A₂4 0, A₁+A₂ 15000x150 +15000x325 15000 15000 (0.237.5)arrow_forwardCentroids and Moment of Inertia for composite figures Determine the centroids (x, ÿ) of the figure shown below from the axes of reference (blue arrows) Use the blue arrows as the axes of reference. 30 Take note that when the axis of reference is not at the end of the figure, the left side / the downward side values must be negative using Varignon's Theorem. Ex: in finding x from the set y-axis, the value of the centroids of individual figures on the left is negative, while on the right side of the figure is positive. R20 Determine the Moment of Inertia (Not Centroidal) of the given figure (Ix) 20. 45 1. Determine x 2.0508, 4.4548,9.4548 , 7.0508 2. Determine y 42.6086 , 49.6088 ,22.3436 ,55.4436 9879988.8980 , 8887788.8980, 7998988.8980 , 8779988.8980 3. Determine Ixarrow_forwardThe moment of inertia of a triangle of base 'b' and height 'h' about Y - Y axis passing through its center of gravity is Select one: dh³/36 bh/36 bh³/12 dh³/12 Shear forces and friction forces always acts along the surfaces and are an example of indirect forces. Select one: True Falsearrow_forward
- I have uploaded answer with questions. Just give valid reason for answers.arrow_forwardQ5: Find the both moments of inertia (Ix, ly) by integration around the central coordinates as shown in next figure. (15 degrees)arrow_forward4. Please answer in correct solution and answer. Please typewritten for upvote.arrow_forward
- Determine the moment of inertia (in mm4) of the given figure with respect to y axis if y=96 mm and z=54 mm. Round off only on the final answer expressed in whole number.arrow_forwardFor the following area, determine: a) the coordinates of the geometric center of the area taking the axes shown in the figure as a reference. Consider b = 36 cm.Adopt π = 3.14159. b) the moments of inertia about the axes that pass through the geometric center of the area. (IxCG = IyCG in cm4)arrow_forwardDetermine the following statement that is true regarding Mohr's Circle. Reference points on Mohr's Circle from two perpendicular axes on the cross-section can lie at angles smaller than 180 degrees relative to each other. Mohr's Circle can't be used to identify angles between principal and non-principal axes. Mohr's Circle contains all possible moment of inertia and product of inertia values for a given fixed area about all rotated axes around the same origin. A reference point on Mohr's Circle that corresponds to one of the principal axes can lie at coordinates of (492, 18.7). The center of Mohr's Circle can only be calculated using principal moments of inertia.arrow_forward
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