För the following function f(x,y,z) = sin(3x+ y? +z²) (3 minutes) O a. f,=6xcos(3x? +y² + z²), f, = 2ycos(3x2+y² +z?) and f,= cos(3x²+y² + z° %3D b. fy=6xcos(3x+y² +z?), fy=2ycos (3x²+y² +z²) and f,=2zcos(3x² +y² + z c. fy=6xcos(3x?+y? +z?), fy=ycos(3x?+y² +z?) and f, = 2zcos(3x² +y² + z® %3D d. fy=xcos(3x?+y? +z?), f,=2ycos(3x²+y² +z?) and f ; = 2zcos(3x² +y² %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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For the following function
f(x,y,z) = sin(3x² +y²+z?)
(3 minutes)
O a. fy=6xcos(3x² +y? + z²), fy =2ycos(3x²+y² +z?) and f,= cos(3x² +y² +z®)
%3D
b. fy=6xcos(3x² +y? +z?) , f, =2ycos(3x²+y²+z?) and f=2zcos(3x²+y²+z
%3D
c. fy=6xcos(3x?+y? +z²), fy=ycos(3x?+y² +z²) and f , = 2zcos(3x²+y² +z®)
%3D
d. fy= xcos(3x+y² +z²), f , =2ycos(3x2+y²+z?) and f;=2zcos(3x²+y²+z²)
%3D
Transcribed Image Text:For the following function f(x,y,z) = sin(3x² +y²+z?) (3 minutes) O a. fy=6xcos(3x² +y? + z²), fy =2ycos(3x²+y² +z?) and f,= cos(3x² +y² +z®) %3D b. fy=6xcos(3x² +y? +z?) , f, =2ycos(3x²+y²+z?) and f=2zcos(3x²+y²+z %3D c. fy=6xcos(3x?+y? +z²), fy=ycos(3x?+y² +z²) and f , = 2zcos(3x²+y² +z®) %3D d. fy= xcos(3x+y² +z²), f , =2ycos(3x2+y²+z?) and f;=2zcos(3x²+y²+z²) %3D
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