For the equilibrium 21Br(g) 12(g) + Br2(g) Kc = 8.50 × 10³ at 150 °C. If 0.0600 mol of IBr is placed in a 1.0-L container, what is the partial pressure of 1₂(g) in atm after equilibrium is reached?

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Q: For the equilibrium 2IBr(g) ⇌ I₂(g) + Br₂(g) Kc = 8.50 × 10⁻³ at 150°C. If 0.0410 mol of IBr is…

A: Working formula: Partial pressure of I2 at equilibrium would be = mole fraction*PTotal  Total…

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Q: For the equilibrium 2IBr(g) ⇌ I₂(g) + Br₂(g) Kc = 8.50 × 10⁻³ at 150 °C. If 0.0540 mol of IBr is…

A: We will first convert the moles of IBr to concentration and then we will find the equilibrium…

Q: reaction vessel mol ¹12, mol 12, and 3.91 mol e at 493°C for the reaction of hydrogen and iodine to…

A: Given -> Volume=V = 13.9 L  T = 493°C  Mole of H2 = 0.873 mole  Mole of I2 = 0.357 mole  Mole of…

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Q: For the equilibrium 2IBr(g) ⇌ I₂(g) + Br₂(g) Kc = 8.50 \times 10⁻^3 at 150 \deg C. If 0.0550 mol of…

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Q: At a certain temperature, 0.4011 mol of N₂ and 1.501 mol of H₂ are placed in a 4.50 L container.…

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Q: In the uncatalyzed reaction N₂O₂(g) = 2 NO₂ (s) at 100 °C, the pressure of the gases at equilibrium…

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Q: When 2.00 mol of N2 gas and 3.00 mol of O2 gas were combined in a 4.0 L cylinder (at 385 °C) there…

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Q: Suppose a 250. mL flask is filled with 1.5 mol of CO, 0.50 mol of H₂O and 1.2 mol of CO2. The…

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.