For the equilibrium 21Br(g) 12(g) + Br2(g) Kc = 8.50 × 10³ at 150 °C. If 0.0600 mol of IBr is placed in a 1.0-L container, what is the partial pressure of 1₂(g) in atm after equilibrium is reached?

Suppose a 500. mL flask is filled with 1.6 mol of H₂ and 0.30 mol of HI. This reaction becomes possible: H₂(g) + 12₂(g) → 2HI(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of I2. You can leave out the M symbol for molarity. initial change equilibrium H₂ 0 1₂ x 0 HI 0 X S

Suppose a 250. mL flask is filled with 1.6 mol of Br₂, 0.70 mol of OC12 and 0.50 mol of BrCl. The following reaction becomes possible: Br₂(g) + OC1₂(g) → BrOC1 (g) + BrCl(g) The equilibrium constant K for this reaction is 2.87 at the temperature of the flask. Calculate the equilibrium molarity of Br₂. Round your answer to two decimal places. M Ś

Consider the following equation:                        N2(g) + 2O2(g) + heat  <=>  2 NO2(g)  In what way will the equilibrium shift when the following stresses occur? The temperature is increased.  More N2 is added.  NO2 is collected and removed.  The pressure is increased.

Steam reforming of methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 200. mL flask with 4.2 atm of methane gas and 2.8 atm of water vapor, and when the mixture has come to equilibrium measures the partial pressure of carbon monoxide gas to be 2.5 atm. Calculate the pressure equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits.

Use the References to access important values if needed for this question. The equilibrium constant, K for the following reaction is 6.50×10 at 298K. 2NOBR(g)=2NO(g) + Br,(g) If an equilibrium mixture of the three gases in a 17.2 L container at 29SK contains 0.369 mol of NOBR(g) and 0.435 mol of NO, the equilibrium concentration of Br, is M.

Suppose a 250. mL flask is filled with 1.4 mol of CO, 1.9 mol of H₂O and 1.0 mol of CO₂. The following reaction becomes possible: CO(g) + H₂O(g) + CO₂(g) + H₂(g) 2 The equilibrium constant K for this reaction is 9.28 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. M X Ś ?

A chemist is studying the following equilibirum, which has the given equilibrium constant at a certain temperature: -6 N, (g) + 3 H, (g) = 2 NH3 (g) К, — 3. х 10 He fills a reaction vessel at this temperature with 6.0 atm of nitrogen gas and 3.2 atm of hydrogen gas. Use this data to answer the questions in the table below. Can you predict the equilibrium pressure of NH3, using only the yes x10 tools available to you within ALEKS? no If you said yes, then enter the equilibrium pressure of NH, at right. atm Round your answer to 1 significant digit.

Steam reforming of methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 5.0 L flask with 3.4 atm of methane gas and 2.2 atm of water vapor, and when the mixture has come to equilibrium measures the partial pressure of carbon monoxide gas to be 0.88 atm. Calculate the pressure equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits. 0 x10 X

Suppose a 500. mL flask is filled with 1.9 mol of Cl₂, 1.5 mol of CHC13 and 0.60 mol of HC1, The following reaction becomes possible: Cl₂(g) + CHC1₂(g) → HC1(g) +CC1₂(g) The equilibrium constant K for this reaction is 9.28 at the temperature of the flask. Calculate the equilibrium molarity of HC1. Round your answer to two decimal places. OM X