For the equation below, if you want 35 mL of H2S2 (1.334 g/mL), what mass of 2.4 % LiCN solution will you make? 2 HCN + 2 Li2S -> 4 LiCN + H2S2 Please note: If you examine the equation carefully, you will see that it is not balanced correctly (and in fact cannot be balanced). Nevertheless, do NOT correct the coefficients or the chemical substances. Use the equation as it has been given to you. 223 g 969 g 3878 g 7782 g
For the equation below, if you want 35 mL of H2S2 (1.334 g/mL), what mass of 2.4 % LiCN solution will you make? 2 HCN + 2 Li2S -> 4 LiCN + H2S2 Please note: If you examine the equation carefully, you will see that it is not balanced correctly (and in fact cannot be balanced). Nevertheless, do NOT correct the coefficients or the chemical substances. Use the equation as it has been given to you. 223 g 969 g 3878 g 7782 g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the equation below, if you want 35 mL of H2S2 (1.334 g/mL), what mass of 2.4 % LiCN solution will you make?
2 HCN + 2 Li2S -> 4 LiCN + H2S2
Please note: If you examine the equation carefully, you will see that it is not balanced correctly (and in fact cannot be balanced). Nevertheless, do NOT correct the coefficients or the chemical substances. Use the equation as it has been given to you.
223 g
969 g
3878 g
7782 g
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