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For the equation 2K + Cl2------>2KCl. I understand Cl is diatomic , but where does the 2 in front of the K come from.

For the equation 2K + Cl2------>2KCl. I understand Cl is diatomic , but where does the 2 in front of the K come from.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the equation 2K + Cl2------>2KCl. I understand Cl is diatomic , but where does the 2 in front of the K come from. 

10:04 M Answered: upplemental Problems. https://www.bartleby.com/questions-and-ans.. = bartleby A Q&A I 0 Science / Chemis... / Q&A Libr... / upplemental Problems f... upplemental Problems from Chapter 2 CC... Mass of Cl2=8. 178g Mass of Cl2 unreacted=6. 867g Step 2 Mass of Cl2 reacted=total Cl2 тass of Clz иnreacte =8. 178g – 6. 867g =1.311g Molar mass of Cl2=70. 906g Mass of Cl, reacted Moles of Cl2 reacted=" Molar mass of Cl2 1.311g 70.906g =0. 01849moles The balanced reaction is given a 2K + Cl2 → 2KCI according to the reaction, 1 mol of Cl2=2 moles of KCl therefore, 0. 01849moles of Cl2=2× 0.01849 moles of KCI =0. 03698moles of KCl Molar mass of KCl=74. 5513g/mol Mass of KCl formed=moles of KCl × molar mass of k =0. 03698 mol × 74. 5513g/mol =2. 757g II
Transcribed Image Text:10:04 M Answered: upplemental Problems. https://www.bartleby.com/questions-and-ans.. = bartleby A Q&A I 0 Science / Chemis... / Q&A Libr... / upplemental Problems f... upplemental Problems from Chapter 2 CC... Mass of Cl2=8. 178g Mass of Cl2 unreacted=6. 867g Step 2 Mass of Cl2 reacted=total Cl2 тass of Clz иnreacte =8. 178g – 6. 867g =1.311g Molar mass of Cl2=70. 906g Mass of Cl, reacted Moles of Cl2 reacted=" Molar mass of Cl2 1.311g 70.906g =0. 01849moles The balanced reaction is given a 2K + Cl2 → 2KCI according to the reaction, 1 mol of Cl2=2 moles of KCl therefore, 0. 01849moles of Cl2=2× 0.01849 moles of KCI =0. 03698moles of KCl Molar mass of KCl=74. 5513g/mol Mass of KCl formed=moles of KCl × molar mass of k =0. 03698 mol × 74. 5513g/mol =2. 757g II
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