For the ECL inverter shown in the following sketch, the high voltage level is VH = -1.7V and the average power dissipated when the input is high 50% of the time is P = 5mW. Determine the source's current IEE, the low voltage level VL, the reference voltage level VREF and the value of resistance R3.

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For the ECL inverter shown in the following sketch, the high voltage level is VH = -1.7V and
the average power dissipated when the input is high 50% of the time is P= 5mW. Determine
the source's current IEE, the low voltage level VL, the reference voltage level VREF and the
value of resistance R3.
2ks2
2k2
VACF
-3.3V
-5.2V
The ECL inverter is the circuit shown. I don't
understand what missing. All the information
needed is stated.
Transcribed Image Text:For the ECL inverter shown in the following sketch, the high voltage level is VH = -1.7V and the average power dissipated when the input is high 50% of the time is P= 5mW. Determine the source's current IEE, the low voltage level VL, the reference voltage level VREF and the value of resistance R3. 2ks2 2k2 VACF -3.3V -5.2V The ECL inverter is the circuit shown. I don't understand what missing. All the information needed is stated.
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