For the cross section shown, calculate the tensile capacity of the steel plate. Assume that the bolt hole is 1/16 inch larger than bolt diameter.
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- Prepare an excel file and to find a) area of the bolt, b) Average Shear Stress Bolt c) Bearing Area Stress and d) allowable stress. Applied force range – 500 to 1000 N (in step of 100 N) Bolt diameter range – 10 to 25 mm (in step of 5 mm) Plate thickness – 10 mm Consider ultimate tensile strength as 460 N/mm2. And consider factor of safety as 1.5.Topic:Bolted Steel Connection - Civil Engineering *Use latest NSCP/NSCP 2015 formula to solve this problem The butt connection shows 8-22 mm dia. A325 bolts spaced as follows: S1 = 40 mm S3 = 50 mm t1 = 16 mm S2 = 80 mm S4 = 100 mm t2 = 12 mm Steel strength and stresses are: Fy = 248 MPa Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Bolt Hole diameter = 25 mm Questions: Calculate the allowable tensile load T, under the following conditions. a) Based on the gross area of the plate b) Based on the net area of the plate c) Based on block shear strengthThe butt connection shows 8-22 mm diameter bolts spaced as shown below. P- 50 100 50 50 100 50 16 mm +HHHH 40 80 40 12 mm Steel strength and stresses are: Yield strength, Fy = 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Based on the gross area of the plate. Based on the net area of the plate. Based on block shear strength. Bolt hole diameter = 25 mm Calculate the allowable tensile load, P, under the following conditions:
- The diagonal at the left to the connection is a double angle 90 mm x 90 mm x 8 mm, with area of 2700 mm?, bolted to the 8 mm thick gusset plate. Bolt diameter = 16 mm Bolt hole diameter = 18 mm Bolt bearing capacity, Fp = 480 MPa Bolt shear strength, Fv = 68 MPa Steel plate strength and stresses are as follows: Yield strength, Fy 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 0.60 Fy Allowable tensile stress on the net area = %3D 0.50 Fu Allowable shear stress on the net area = 0.30 Fu Bolt bearing capacity, Fp = 1.2 Fy Calculate the allowable tensile load, P(kN) under the following conditions: %3DTopic:Bolted Steel Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A 12.5 mm x150 mm plate is connected to a gusset plate having a thickness of 9.5 mm.Diameter of bolt = 20 mm Both the tension member and the gusset plate are of A 36 steel. Fy = 248 MPa, FU = 400 MPa. Shear stress of bolt Fnv = 300MPa. Questions: a.Determine the shear strength of the connection. b.Determine the bearing strength of the connection. c. Determine the block shear strength of the connection.A bearing type connection is shown in Figure 3.19. The diameter of A 325 bolts is 22 mm and the A572 Grade 50 plate material has a width of 150 mm and thickness of 16 mm. Assume diameter hole to be 24 mm. Bolt threads are excluded from the shear plane. Allowable stress of A 325 bolts: Fv = 207 MPa Fp = 1.5 Fu (to prevent excessive hole deformation) Allowable stresses of A572 Grade 50 plate material: Fy = 345 MPa Fu = 450 MPa a. Compute the tensile capacity due to the failure of the plates. b. Compute the tensile capacity due to the failure of the bolts.
- A bolted lap joint is shown in the figure below. The bolts are 19mm in diameter. Effective diameter of the holes is 23mm. The plates are 12 mm thick, x1 = 33 mm, x2 = 76 mm, x3 = 50 mm. Yield strength of plate, Fy = 248 MPa Ultimate tensile strength of plate, Fu = 400 MPa Required: Using allowable strength design: 1. Find the safe load “P” based on gross area yielding. 2. Find the safe load “P” based on net area rupture. 3. Find the safe load “P” based on block shear.What will be the block shear strength of a tension member as shown in figure below? The steel is of grade Fe410. ISA 80 x 50 x 8 50 115 mm mm 18 mm o hole 35 mm 45 mmThe plate shown is 8 in wide and 1/2 in thick. The bolts are 7/8 in. The smallest net area (An) of this bolted plate is equal to:
- 4. As shown below, the splicing joint of a beam was made with bearing type high-strength bolts. The loads transferred through the joint is V=3000KN, M=90KN.m. The bolts are of grade 10.9, nominal diameter 22mm, effective area Ae=2.45cm2;f=310N/ mm?; f-500N/mm²; End plates made of Q235B steel, thickness 22mm, fe-470N/mm?. Check the strength of this bolt connection. -24mm 35 130 35 80 V 1 og1 081 1 081Determine block shear strength of tension member shown in figure if grade of steel is Fe-410 ISA 100 × 75x8 mm 50 100 55 35 O 20 mm dia bolt holeThe connection shows a PL10X200 loaded in tension and welded to a 10mm gusset plate. Calculate the following, assuming A36 steel is used. • The design strength in gross yielding The allowable strength in tensile rupture PL 10 X 200 350mm