For the circuit shown in the figure, calculate the following. (Assume = 8.64 V and R = 6.54 Ω.) A rectangular circuit begins at point a on its left side. On its top side, the circuit splits into two parallel horizontal branches. The top branch contains, from left to right, a 12.0 V battery and a 4.00 Ω resistor. The positive terminal of the battery is to the left of its negative terminal. The bottom branch contains a 2.00 Ω resistor. The top and bottom branches recombine to meet at point b, which is to the right of the branches. The right side of the rectangular circuit extends down from the bottom branch, just to the right of the 2.00 Ω resistor and to the left of point b. The bottom side of the rectangle, from right to left, contains a resistor R and a battery labeled emf ℰ, where its positive terminal is to the right of its negative terminal. The circuit extends to the left from the negative terminal until it reaches point a, completing the circuit. (a) the current in the 2.00-Ω resistor (Enter the magnitude.) A (b) the potential difference between points a and b, ΔV = Vb − Va

A rectangular circuit begins at point a on its left side. On its top side, the circuit splits into two parallel horizontal branches.

The top and bottom branches recombine to meet at point b, which is to the right of the branches. The right side of the rectangular circuit extends down from the bottom branch, just to the right of the 2.00 Ω resistor and to the left of point b. The bottom side of the rectangle, from right to left, contains a resistor R and a battery labeled emf ℰ, where its positive terminal is to the right of its negative terminal. The circuit extends to the left from the negative terminal until it reaches point a, completing the circuit.

ΔV = V_b − V_a