M:26) For the circuit shown in figure below .i, = 4sin(3t) and i, = 1 A. v2 = ?%3D1 H2H1 HSelect one:A. 12.36 sin (3t +14) VB. -12.36 cos 2t VC. 8 cos 2t VD. 12.36 cos 2t VE. 12.36 sin (3t -14) VF. 12.36 cos (3t +14) V

Given Circuit has: i1=4sin3t=+j4 .....+j due to sinwt=+j4∠0° A ω=3∴x1=2 H=j3×2=j6 Ω∴x2=1…

For the circuit shown in figure below .i, = 4 sin(3t) and i, = 1 A. v2 = ? 1 H 2 H 1 H Select one: A. 12.36 sin (3t +14) V B. -12.36 cos 2t V C. 8 cos 2t V D. 12.36 cos 2t V E. 12.36 sin (3t -14) V F. 12.36 cos (3t +14) V

For the circuit shown in figure below .i, = 4 sin(3t) and i, = 1 A. v2 = ? 1 H 2 H 1 H Select one: A. 12.36 sin (3t +14) V B. -12.36 cos 2t V C. 8 cos 2t V D. 12.36 cos 2t V E. 12.36 sin (3t -14) V F. 12.36 cos (3t +14) V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Compensation Techniques

The compensation techniques are the methods that are employed in the electrical control systems to enhance the performance of the system. The performance are generally affected by the factors like lag in the compensating devices, slow response of the system of the components like sensors used in the control system. The basic compensation technique involves lag compensation, lead compensation or the combination of the both.

Question

M:26)

For the circuit shown in figure below .i, = 4
sin(3t) and i, = 1 A. v2 = ?
%3D
1 H
2H
1 H
Select one:
A. 12.36 sin (3t +14) V
B. -12.36 cos 2t V
C. 8 cos 2t V
D. 12.36 cos 2t V
E. 12.36 sin (3t -14) V
F. 12.36 cos (3t +14) V

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