For the Boolean function F (w,x,y,z)= xy'z + x'y'z + w'xy (a) Obtain the truth table. (b) Draw the logic diagram. (c) Use Boolean algebra to simplify the function to a minimum number of literals. (d) Obtain the truth table of the function from the simplified expression (c) and show that it is the same as the one in part (a). (c) Draw the logic diagram from the simplified expression (c).

I really need help answering these questions pls  1. A variable is a symbol in Boolean algebra used to represent(a) data (b) a condition(c) an action (d) answers (a), (b), and (c) 2. The Boolean expression A + B + C is(a) a sum term (b) a literal term(c) an inverse term (d) a product term 3. The Boolean expression ABCD is(a) a sum term (b) a literal term(c) an inverse term (d) a product term 4. The domain of the expression ABCD + AB + CD + B is(a) A and D (b) B only(c) A, B, C, and D (d) none of these 5. According to the associative law of addition,(a) A + B = B + A (b) A = A + A(c) (A + B) + C = A + (B + C ) (d) A + 0 = A 6. According to commutative law of multiplication,(a) AB = BA (b) A = AA(c) (AB)C = A(BC ) (d) A0 = A 7. According to the distributive law,(a) A(B + C) = AB + AC (b) A(BC) = ABC(c) A(A + 1) = A (d) A + AB = A 8. Which one of the following is not a valid rule of Boolean algebra?(a) A + 1 = 1 (b) A = A(c) AA = A (d) A + 0 = A 9. Which of the following rules states that…

Problem 1: Find the dual of a logic function F = (X'Y + Z)W’

Given the following Boolean Function: F(w,x,y,z) = (8,10,12,14) Show the function in the truth table in column F. 1.

Hi just type the answer no need for long explanation

Show the logic diagram for the three-variable expression (a⊕b)c'+(b’a+c(a+b))'+(ac)’ and construct the truth table for it.

Note: - You are attempting question 4 out of 12 Derive the hazard free Boolean expression for given logic function. F(W,X,Y.Z)= m(0,4,5,10,11,13,14,15) (а) АС + ВСD + ACD (b) АС + ВCD + ACD+АВС+ АBD (c) АС + ACD+ ABC + ABD (d) ABC + ABD Answer

Using matlab to compute if you can.

Please make a k-map to simplify the given boolean equation (and list the final simplified expression)(((((Y AND (~Z)) OR ((~Y) AND Z)) OR (~Z)) AND (~(X OR Y))) OR  (~(((Y AND (~Z)) OR ((~Y) AND Z)) OR (~Z))) AND (X OR Y))