Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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### Equilibrium Calculation for [Ag(CN)₂]⁻ Complex

**Problem Statement:**
- For the aqueous \( [\text{Ag}(\text{CN})_2]^{-} \) complex, the formation constant \( K_f = 1.26 \times 10^{21} \) at 25 °C.
- Suppose equal volumes of 0.0022 M AgNO₃ solution and 0.48 M KCN solution are mixed. Calculate the equilibrium molarity of aqueous \( \text{Ag}^+ \) ion.
- Round your answer to 2 significant digits.

**Answer Format:**
- The answer should be provided in molarity (M).

**Diagram Explanation:**
The image contains a rectangular box where the equilibrium molarity of \( \text{Ag}^+ \) ion should be entered. Next to it, there is a small control panel with options to input the response, such as multiplication by 10, a check mark, and a help button.

This setup appears to be from an online educational platform, where students can input their calculated answer and possibly access hints or verify their response.

### Detailed Steps for Solving the Problem:
1. **Mixing Solutions:**
   - Initial concentration of AgNO₃ = 0.0022 M
   - Initial concentration of KCN = 0.48 M
   - When mixed, the concentration of each will halve due to equal volumes mixed:
     - \([ \text{Ag}^+ ]_{\text{initial}} = \frac{0.0022 \text{ M}}{2} = 0.0011 \text{ M}\)
     - \([ \text{CN}^- ]_{\text{initial}} = \frac{0.48 \text{ M}}{2} = 0.24 \text{ M}\)

2. **Formation of Complex Ion:**
   - The reaction for the formation of the complex:
     \[ \text{Ag}^+ + 2 \text{CN}^- \leftrightharpoons [ \text{Ag}(\text{CN})_2 ]^- \]
   - The formation constant expression:
     \[ K_f = \frac{[ \text{Ag}(\text{CN})_2^- ]}{[\text{Ag}^+ ][ \text{CN}^- ]^
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Transcribed Image Text:### Equilibrium Calculation for [Ag(CN)₂]⁻ Complex **Problem Statement:** - For the aqueous \( [\text{Ag}(\text{CN})_2]^{-} \) complex, the formation constant \( K_f = 1.26 \times 10^{21} \) at 25 °C. - Suppose equal volumes of 0.0022 M AgNO₃ solution and 0.48 M KCN solution are mixed. Calculate the equilibrium molarity of aqueous \( \text{Ag}^+ \) ion. - Round your answer to 2 significant digits. **Answer Format:** - The answer should be provided in molarity (M). **Diagram Explanation:** The image contains a rectangular box where the equilibrium molarity of \( \text{Ag}^+ \) ion should be entered. Next to it, there is a small control panel with options to input the response, such as multiplication by 10, a check mark, and a help button. This setup appears to be from an online educational platform, where students can input their calculated answer and possibly access hints or verify their response. ### Detailed Steps for Solving the Problem: 1. **Mixing Solutions:** - Initial concentration of AgNO₃ = 0.0022 M - Initial concentration of KCN = 0.48 M - When mixed, the concentration of each will halve due to equal volumes mixed: - \([ \text{Ag}^+ ]_{\text{initial}} = \frac{0.0022 \text{ M}}{2} = 0.0011 \text{ M}\) - \([ \text{CN}^- ]_{\text{initial}} = \frac{0.48 \text{ M}}{2} = 0.24 \text{ M}\) 2. **Formation of Complex Ion:** - The reaction for the formation of the complex: \[ \text{Ag}^+ + 2 \text{CN}^- \leftrightharpoons [ \text{Ag}(\text{CN})_2 ]^- \] - The formation constant expression: \[ K_f = \frac{[ \text{Ag}(\text{CN})_2^- ]}{[\text{Ag}^+ ][ \text{CN}^- ]^
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