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For TE mode light of 600 (nm) wavelength that is traveling in dielectric 1 and incident on an interface with dielectric 2 at an angle of 85°, what is the phase change of the parallel component of the electric field upon reflection from the interface? The index of refraction for dielectric 1 is n₁ = 1.47 and for dielectric 2, n₂- 1.33? Give your answer in degrees with 4 significant digits. :11

For TE mode light of 600 (nm) wavelength that is traveling in dielectric 1 and incident on an interface with dielectric 2 at an angle of 85°, what is the phase change of the parallel component of the electric field upon reflection from the interface? The index of refraction for dielectric 1 is n₁ = 1.47 and for dielectric 2, n₂- 1.33? Give your answer in degrees with 4 significant digits. :11

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For TE mode light of 600 (nm) wavelength that is traveling in dielectric 1 and incident on an interface with dielectric 2 at an angle of 85°, what is the phase change of the parallel component of the electric field upon reflection from the interface? The index of refraction for dielectric 1 is n₁ = 1.47 and for dielectric 2, n₂ = 1.33? Give your answer in degrees with 4 significant digits. Please solve this problem urgently I will up vote but with clear steps... If you know perfectly
Transcribed Image Text:For TE mode light of 600 (nm) wavelength that is traveling in dielectric 1 and incident on an interface with dielectric 2 at an angle of 85°, what is the phase change of the parallel component of the electric field upon reflection from the interface? The index of refraction for dielectric 1 is n₁ = 1.47 and for dielectric 2, n₂ = 1.33? Give your answer in degrees with 4 significant digits. Please solve this problem urgently I will up vote but with clear steps... If you know perfectly
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