For samples of the specified size from the population described, find the mean andstandard deviation of the sample meanx.The National Weather Service keeps records of snowfall in mountain ranges. Recordsindicate that in a certain range, the annual snowfall has a mean of 83 inches and astandard deviation of 14 inches. Suppose the snowfalls are sampled during randomlypicked years. For samples of size 49, determine the mean and standard deviation of xA) μ=83; 0x=2B) μ = 2; σ= 83OcC) μ = 83; σ= 14D) u 14; = 83=

From the provided information, Mean (µ) = 83 Standard deviation (σ) = 14 X~N (83, 14)

Answered: For samples of the specified size from…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and standard deviation of 1.00degrees C. Assume 2.4% of the thermometers are rejected because they have readings that are too high and another 2.4% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. A. The cutoff values are degrees. (Use a comma to separate answers as needed. Round to two decimal places as needed.)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P80, the 80-percentile. This is the temperature reading separating the bottom 80% from the top 20%.P80 = °C
According to an automobile association, the average cost of a gallon of regular unleaded fuel at gas stations in a certain month was $2.825. Assume that the standard deviation of such costs is $0.15. Suppose that a random sample of n = 100 gas stations is selected from the population and the month's cost per gallon of regular unleaded fuel is determined for each. Consider x, the sample mean cost per gallon. Complete part a through d. Click the icon to view the table of normal curve areas. a. Calculate P and o
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For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 38beats per minute, the mean of the listed pulse rates is x =73.0 beats per minute, and their standard deviation is sequals=23.2 beats per minute. a. What is the difference between the pulse rate of 38 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 38 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 38 beats per minute significant?
For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 37 beats perminute, the mean of the listed pulse rates is x=77.0 beats per minute, and their standard deviation is s=24.8 beats per minute. a. What is the difference between the pulse rate of 37 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 37 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 37 beats per minute significant?
Table 1.6 A biologist measured the width(in mm) of the upper molar in 40 specimens(population) of a certain mammal. These results are given in the ff. fdt. Mean width(mm) frequency 5.5 3 5.8 10 6.1 15 6.4 8 6.7 3 7.0 1 Calculate the mean deviation(MD) and standard deviation(s) to the nearest hundredths. Choose the relationship which will describe the fdt in terms of variation. Group of answer choices A. None of the measures describes the variation. B. The standard deviation is more variable than the mean deviation. C. Equal variation. D. The mean deviation is more variable than the standard deviation.
Given the following mean and standard deviation, find the z-score for each individual score. Find the difference between the data value and the mean then divide by the standard deviation. X = 10 a. X= 8 s = 2 Z = %3D b. X= 38 X = 40 s = 5 Z = С. X%3D94 X = 100 s = 10 z = d. X= 65 X = 50 s = 10 Z = %3D e. X= 30 X = 25 s = 5 Z =
Assume that the distribution of scores on a college entrance exam is normally distributed with a mean of 490 and a standard deviation of 43. For each score in the table below, convert the raw score into a corresponding z-score. original score Z-score 621 398 586 710
Two companies, A and B, drill wells in a rural area. Company A charges a flat fee of 3095 dollars to drill a well regardless of its depth. Company B charges 1180 dollars plus 9 dollars per foot to drill a well. The depths of wells drilled in this area have a normal distribution with a mean of 240 feet and a standard deviation of 35 feet. Find the mean amount charged by Company B to drill a well. Enter the exact answer. μ = i dollars

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