For R1=40, R2=60, R3-60, R4-30, R5=30, V1-10 V, V2=40 V & 11=8 A in the circuit shown below, apply sourcetransformation to find Vx (in volt)R1wwR3R5wwwV1R2O a. -81.212121212121O b. 40.606060606061c. -40.606060606061O d. -121.81818181818wwwI1R4V2

given here a circuit and asked to find Vx using source transformation.

For R1=40, R2=60, R3-60, R4-30, R5=30, V1=10 V, V2=40 V & 11=8 A in the circuit shown below, apply source transformation to find Vx (in volt) R3 R1 ww R5 www V1( www R2 a. -81.212121212121 11 www R4 V2

For R1=40, R2=60, R3-60, R4-30, R5=30, V1=10 V, V2=40 V & 11=8 A in the circuit shown below, apply source transformation to find Vx (in volt) R3 R1 ww R5 www V1( www R2 a. -81.212121212121 11 www R4 V2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

For R1=40, R2=60, R3-60, R4-30, R5=30, V1-10 V, V2=40 V & 11=8 A in the circuit shown below, apply source
transformation to find Vx (in volt)
R1
ww
R3
R5
www
V1
R2
O a. -81.212121212121
O b. 40.606060606061
c. -40.606060606061
O d. -121.81818181818
www
I1
R4
V2

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