For part a and b, explain what is wrong with the statement. a. 3x+1 2x dx = S*** + C x+x %3D n+1 b. For all n, S x" dx = + C %3D n+1

Q: 3(2x-1/2)=16

A:

Q: 00 2x 10 Vx+1

A:

Q: J(x-3x)dx = x' 3x +C 2 -3х + С 4 b. 3x-3+C 3x+C 4 4x* -6x +C

A:

Q: 2/3x=-8/3

A:

Q: |4x – x² dx

A: Given query is to find the value of integral.

Q: 2/3x+1/2=2/5

A:

Q: Find two First terms whose product is 3x. 3x? – 13xy + 4y² = (3x ?y)(x ?y)

A: Given that, 3x2-13xy+4y2=3x    ?yx   ?y

Q: 3x+3/3 < 3

A: We need to find the values of x for the given inequality holds good

Q: Evaluate S (2x+3) dx x² (x²+1)

A:

Q: X2 dx ex+3

A:

Q: 8 - 128x V81 - 64x2 "xp-

A:

Q: x + ax – 2bx - 2ab – x - 2ax - 2bx dx x* + ax? – 2bx² – 2abx?

A:

Q: Find the following

A: ∫(8x3+10x2-7x+5) dx

Q: d (ae dx 3lnx 3x -

A:

Q: -dx 2x3/2 — Зх2

A: Given : ∫x2x32-3x2dx ∫x2x32-3x2dx = -∫x3x2-2x32dx Now, let us solve ∫x3x2-2x32dx Let us take  u=x⇒…

Q: Evaluate [x³e³dx

A:

Q: Statements 1. -6(2x +1) = -11x – 7x 2. -12x – 6 = -18x 3. -6 = -6x 4. 1 =X

A:

Q: ax +-b dx ax² +bx +d

A:

Q: y = 1/2x + 5

A:

Q: dx 5+ x2

A: For knowledge purpose we will derive the general formula for such type of integration.

Q: sx2-9x-6 dx x3-2x2- 4xt8

A:

Q: V9 – 4x2 dx

A: