For each of the indefinite integrals below, the main question is to decide whether the integral can be evaluated using u-substitution, integration by parts, a combination of the two, or neither. For integrals for which your answer is affirmative (u-sub, by parts, combo), state the substitution you would use. It is not necessary to actually evaluate any of the integrals completely, unless the integral can be evaluated immediately using a famil TABLE A 2³sin(2³) de [2²sin(x) da sin(2¹) dz zsin(2¹) de Method u-Sub By Parts Combo Neither V W= 4. 1. du = 1. In TABLE B, assume you know the antiderivative of tan (2). Further, answer the questions without doing any simple algebraic manipulations. TABLE B dz ? Method u

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For each of the indefinite integrals below, the main question is to decide whether the integral can be evaluated using u-substitution, integration by parts, a combination of the two, or neither.
For integrals for which your answer is affirmative (u-sub, by parts, combo), state the substitution you would use. It is not necessary to actually evaluate any of the integrals completely, unless the integral can be evaluated immediately using a familiar basic antiderivative.
TABLE A
[2² sin (2³) de
[ 2² sin(2) dr
[sin(2³) da
[ 2³ sin(2³) de
Method
?
u-Sub
By Parts
Combo
Neither
U=
du =
In TABLE B, assume you know the antiderivative of tan-¹(r). Further, answer the questions without doing any simple algebraic manipulations.
TABLE B
₁2 de
1₁
2x+3
1 + x2
TABLE C
[₁+ (²²
In(x)
[xln(x) dx
de
fin(1+a
[2ln(1
da
dx
TABLE D
+x²) dx
√1-
de
[2√1-² dr
而
2
?
?
L"
da
xv1-
?
r In(1+x²) da?
?
?
?
dx ?
da ?
?
Method
Method
V
Method
u=
u=
4
4
A
4
A
du =
dv=
du =
Transcribed Image Text:For each of the indefinite integrals below, the main question is to decide whether the integral can be evaluated using u-substitution, integration by parts, a combination of the two, or neither. For integrals for which your answer is affirmative (u-sub, by parts, combo), state the substitution you would use. It is not necessary to actually evaluate any of the integrals completely, unless the integral can be evaluated immediately using a familiar basic antiderivative. TABLE A [2² sin (2³) de [ 2² sin(2) dr [sin(2³) da [ 2³ sin(2³) de Method ? u-Sub By Parts Combo Neither U= du = In TABLE B, assume you know the antiderivative of tan-¹(r). Further, answer the questions without doing any simple algebraic manipulations. TABLE B ₁2 de 1₁ 2x+3 1 + x2 TABLE C [₁+ (²² In(x) [xln(x) dx de fin(1+a [2ln(1 da dx TABLE D +x²) dx √1- de [2√1-² dr 而 2 ? ? L" da xv1- ? r In(1+x²) da? ? ? ? dx ? da ? ? Method Method V Method u= u= 4 4 A 4 A du = dv= du =
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