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- Lemingtons is trying to determine how many Jean Hudson dresses to order for the spring season. Demand for the dresses is assumed to follow a normal distribution with mean 400 and standard deviation 100. The contract between Jean Hudson and Lemingtons works as follows. At the beginning of the season, Lemingtons reserves x units of capacity. Lemingtons must take delivery for at least 0.8x dresses and can, if desired, take delivery on up to x dresses. Each dress sells for 160 and Hudson charges 50 per dress. If Lemingtons does not take delivery on all x dresses, it owes Hudson a 5 penalty for each unit of reserved capacity that is unused. For example, if Lemingtons orders 450 dresses and demand is for 400 dresses, Lemingtons will receive 400 dresses and owe Jean 400(50) + 50(5). How many units of capacity should Lemingtons reserve to maximize its expected profit?If the number of competitors in Example 11.1 doubles, how does the optimal bid change?The Tinkan Company produces one-pound cans for the Canadian salmon industry. Each year the salmon spawn during a 24-hour period and must be canned immediately. Tinkan has the following agreement with the salmon industry. The company can deliver as many cans as it chooses. Then the salmon are caught. For each can by which Tinkan falls short of the salmon industrys needs, the company pays the industry a 2 penalty. Cans cost Tinkan 1 to produce and are sold by Tinkan for 2 per can. If any cans are left over, they are returned to Tinkan and the company reimburses the industry 2 for each extra can. These extra cans are put in storage for next year. Each year a can is held in storage, a carrying cost equal to 20% of the cans production cost is incurred. It is well known that the number of salmon harvested during a year is strongly related to the number of salmon harvested the previous year. In fact, using past data, Tinkan estimates that the harvest size in year t, Ht (measured in the number of cans required), is related to the harvest size in the previous year, Ht1, by the equation Ht = Ht1et where et is normally distributed with mean 1.02 and standard deviation 0.10. Tinkan plans to use the following production strategy. For some value of x, it produces enough cans at the beginning of year t to bring its inventory up to x+Ht, where Ht is the predicted harvest size in year t. Then it delivers these cans to the salmon industry. For example, if it uses x = 100,000, the predicted harvest size is 500,000 cans, and 80,000 cans are already in inventory, then Tinkan produces and delivers 520,000 cans. Given that the harvest size for the previous year was 550,000 cans, use simulation to help Tinkan develop a production strategy that maximizes its expected profit over the next 20 years. Assume that the company begins year 1 with an initial inventory of 300,000 cans.
- Maximize C- 16A + 21B subject to 9A +15B $22 10A + 3B ≤ 29 and A≥0, B20. What is the optimal value of A? O 2.444 O 0.000 39.11 O 4.222LPP Model Maximize P = 12x + 10y Subject to : 4x + 3y < 480 2x + 3y < 360 X, y 2 0 Which of the following points (x, y) is feasible? A) ( 120, 10) B ( 30, 100 ) c) ( 60, 90 ) D) ( 10, 120 )Palmer Jam Company is a small manufacturer of several different jam products. One product is an organic jam that has no preservatives, sold to retail outlets. Susan Palmer must decide how many cases of jam to manufacture each month. The probability that demand will be 5 cases is 0.10, for 6 cases it is 0.30, for 7 cases it is 0.50, and for 8 cases it is 0.10. The cost of every case is $40, and the price Susan gets for each case is $85. Unfortunately, any cases not sold by the end of the month are of no value as a result of spoilage. Based on the given information, Susan's conditional profits table for jam is: Demand 5 cases 6 cases 7 cases 8 cases Produce p= 0.10 p = 0.30 p= 0.50 p = 0.10 5 cases 6 cases 7 cases 8 cases The number of cases that Susan should produce to achieve maximum expected value (EMV) is cases. The EMV of stocking this number of cases is $ (round your answer to the nearest whole number).
- Palmer Jam Company is a small manufacturing of several different jam products. One product is an organic jam that has no preservatives, sold to retail outlets. Susan Palmer must decide how many cases of jam to manufacture each month. The probability that demand will be 6 cases is .1, for 7 cases it is .3 , for 8 cases it is .5, and for 9 cases it is .1. The cost of every case is $45 and the price Susan gets for each case is $95. Unfortunately, an cases not sold by the end of the month are of no value as a result of spoilage. How many cases should susan manufacture each monthPalmer Jam Company is a small manufacturer of several different jam products. One product is an organic jam that has no preservatives, sold to retail outlets. Susan Palmer must decide how many cases of jam to manufacture each month. The probability that demand will be 5 cases is 0.10, for 6 cases it is 0.25, for 7 cases it is 0.50, and for 8 cases it is 0.15 The cost of every case is $45, and the price Susan gets for each case is $90. Unfortunately, any cases not sold by the end of the month are of no value as a result of spoilage. Based on the given information, Susan's conditional profits table for jam is: Demand 5 cases 6 cases 7 cases 8 cases Produce =0.10 0.25 0.50 0.15 5 cases Note:- Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. Answer completely. You will get up vote for sure.Maximize Profit=123 L + 136 S 17 L+11 S≤ 3000 6 L+9 S≤2500 L20 and S20 (Availability of component A) (Availability of component B) Show Transcribed Text Implement the linear optimization model and find an optimal solution. Interpret the optimal solution. The optimal solution is to produce LaserStop models and SpeedBuster models. This solution gives the possible profit, which is $. (Type integers or decimals rounded to two decimal places as needed.)
- Palmer Jam Company is a small manufacturer of several different jam products. One product is an organic jam that has no preservatives, sold to retail outlets. Susan Palmer must decide how many cases of jam to manufacture each month. The probability that demand will be 7 cases is 0.10, for 8 cases it is 0.25, for 9 cases it is 0.45, and for 10 cases it is 0.20. The cost of every case is $50, and the price Susan gets for each case is $90. Unfortunately, any cases not sold by the end of the month are of no value as a result of spoilage. Based on the given information, Susan's conditional profits table for jam is: Demand 7 cases 8 cases 9 cases 10 cases Produce p=0.10 p=0.25 p=0.45 p=0.20 7 cases enter your response here enter your response here enter your response here enter your response here 8 cases enter your response here enter your response here enter your response here enter your response here…Palmer Jam Company is a small manufacturer of several different jam products. One product is an organic jam that has no preservatives, sold to retail outlets. Susan Palmer must decide how many cases of jam to manufacture each month. The probability that demand will be 7 cases is 0.10, for 8 cases it is 0.25, for 9 cases it is 0.45, and for 10 cases it is 0.20. The cost of every case is $50, and the price Susan gets for each case is $90. Unfortunately, any cases not sold by the end of the month are of no value as a result of spoilage. Based on the given information, Susan's conditional profits table for jam is: Demand 7 cases 8 cases 9 cases 10 cases Produce p=0.10 p=0.25 p=0.45 p=0.20 7 cases enter your response here enter your response here enter your response here enter your response here 8 cases enter your response here enter your response here enter your response here enter your response here…8. Palmer Jam Company is a small manufacturer of several different jam products. One product is an organic jam that has no preservatives, sold to retail outlets. Susan Palmer must decide how many cases of jam to manufacture each month. The probability that demand will be 5 cases is 0.05, for 6 cases it is 0.30, for 7 cases it is 0.50, and for 8 cases it is 0.15. The cost of every case is $45, and the price Susan gets for each case is $90. Unfortunately, any cases not sold by the end of the month are of no value as a result of spoilage. Part 2 Based on the given information, Susan's conditional profits table for jam is: Demand 5 cases 6 cases 7 cases 8 cases Produce p=0.05 p=0.30 p=0.50 p=0.15 5 cases __________ ___________ ___________ ____________ b) The number of cases that Susan should produce to achieve maximum expected value (EMV) is _____ cases. c) The EMV of stocking this number of cases is $_______.