For each of the following regression models, indicate whether it is a general linear regres- sion model. If it is not, state whether it can be expressed in the form of (6.7) by a suitable transformation: a. Y; = ßo + ß₁X¿¡1 + ß2 log10 Xi2 + ß³X²₁ + ɛi b. Y; = ɛ; exp(ßo + ß₁ס1 + ß₂X²/2) c. Y; = log10(81X;1) + B2Xi2 + εi d. Y;=ẞo exp(ẞ₁X¡1) + εi e. Y; = [1+exp(ßo + B₁X₁₁ + ε¡)]¯¯¹ General Linear Regression Model In general, the variables X₁,..., X-1 in a regression model do not need to represent different predictor variables, as we shall shortly see. We therefore define the general linear 18 Part Two Multiple Linear Regression regression model, with normal error terms, simply in terms of X variables: Y₁ = Bo+B₁Xi1 + B2X12 ++ Bp-1Xi,p-1 +εi where: Bo, B1, Xi Xi,p-1 are known constants Bp-1 are parameters &, are independent N(0, 2) i=1,...,n (6.7)

Jessica says she doesn’t understand the Pythagorean theorem. She put numbers in for a, b, and c in the equation a2 + b2 = c2, but the equation isn’t always true. For example, when she put in a = 2, b = 3, and c = 4, she got 4 + 9 = 16, which isn’t correct. Jessica wants to know why the Pythagorean theorem isn’t working. Write an informative paragraph discussing Jessica’s conundrum. Why does the Pythagorean theorem appear not to be correct? What misunderstanding does Jessica have? Beckmann, Sybilla. Mathematics for Elementary Teachers with Activities, (p. 576). Pearson Education. Kindle Edition.

A student thinks that the expressions (a + b) and a + b- are equal to one another. How would you explain to the student why this is not so? Choose the correct answer below. This is because, for example, (a + b) is equal to when a= 4 and b = 6, while a +b² is equal to not so so

If we use the missing-addend approach to solve the problem 10 + = x, which is more correct to write: 10 = 6 + x, or 10 = x + 6? Explain.

what is the answer to c - (-14) = -14

I was given the solution to 63 = 28-5(x-3) as -4 but I can't seem to figure out that solution for myself.

When I put 2+1 or 3 as the answer it said I got the question wrong? Did I perhaps misread your response?