Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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## Initial Value Problems and Solutions

**Problem 3:** For each of the following initial value problems, write down a formula for the solution \( x(t) \) and determine its maximal interval of existence.

### (a)
\[ \dot{x} = x^2 - 4 \quad \text{with} \quad x(0) = 0 \]

### (b)
\[ \dot{x}_1 = x_1^2, \quad \dot{x}_2 = x_2 + x_1^{-1} \quad \text{with} \quad x_1(0) = 1, \quad x_2(0) = 1 \] 

In this problem, the objective is to find solutions \( x(t) \) based on the given initial conditions and determine the interval over which these solutions are valid.
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Transcribed Image Text:## Initial Value Problems and Solutions **Problem 3:** For each of the following initial value problems, write down a formula for the solution \( x(t) \) and determine its maximal interval of existence. ### (a) \[ \dot{x} = x^2 - 4 \quad \text{with} \quad x(0) = 0 \] ### (b) \[ \dot{x}_1 = x_1^2, \quad \dot{x}_2 = x_2 + x_1^{-1} \quad \text{with} \quad x_1(0) = 1, \quad x_2(0) = 1 \] In this problem, the objective is to find solutions \( x(t) \) based on the given initial conditions and determine the interval over which these solutions are valid.
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Hi! As per norm, we will be solving only the first question. If you need an answer to the other then kindly repost the question by specifying it.

For (a),

We need to solve x˙=x2-4 with x(0)=0.

So,

                 x˙=x2-4dxdt=x2-41x2-4dx=dtIntegrating both sides we get,1x2-4dx=dt-14lnx2+1-lnx2-1=t+c1

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