For an air (n=1) and glass (n=1.45) interface, determine the % of the light reflected (reflectance) and transmitted (transmittance) for a light beam incident from air to glass with (a) incident angle = 25o and the electric field (polarization) direction is in the incident plane, (b) incident angle=25o and electric field (polarization) direction is 45o with respect to the incident plane.

Light enters a material with index of refraction n from air.(a)What is the speed of light in the material, if the critical angle is 47◦? (b)If the light has wavelength 500nm in a vacuum, what is its wavelength in the material? (c)What is its frequency?

Light, when incident on a given surface, presents a reflected and a refracted component. When the reflected beam is perpendicular to the refracted beam, the angle of incidence θᵢ is called Brewster's angle. If a beam of light is initially in air with index of refraction n₁ = 1 and is incident on a glass surface (index of refraction n₂ = 1.5), Brewster's angle is: a)82.9° b)36.3° c)75.4° d)62.9° e)56.3° f)45.7°

E₁ H₁ X OR ET E₁ tTE = ER HT ET HR ns Transverse Electric, TE nu The Figure above shows TE polarised light incident on a dielectric interface. Light is in- cident from the upper left, in a sourced medium with refractive index ng at an angle of incidence 0₁, onto an unsourced medium with refractive index nu, and transmitted at angle of refraction T. Both media are non-magnetic. The vectors H₁, HR, HT are the magnetic fields for incident, reflected and transmitted waves respectively; the corresponding E fields point into the paper, as shown by the arrow-tail symbols. State the boundary conditions on the E and H fields, then use these to prove that the amplitude transmission coefficient tre is given by Z 2ng cos 01 ng cos 0₁ + nu cos OT (Justify any assumption relating impedance to refractive index).