For a t distribution with 16 degrees of freedom, find the area, or probability, in each region. (Round your answers to three decimal places.) A. to the right of 2.120 B. between −2.583 and 2.583 C. between −1.746 and 1.746

Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. The area of the shaded region is needed.) 108 122 (Round to four decimal places as O

calculate probability of the given Z scores:  mean= 0 SD= 1 Given Z scored: -3, -2,-1, 0, 1, 2, 3

In each part, find the area under the standard normal curve that lies between the specified z-score, sketch a standard normal curve, and shade the area of interest. b. -2 and 2 c. - 3 and 3 a. - 1 and 1 a. Find the area under the standard normal curve that lies between - 1 and 1, sketch a standard normal curve, and shade the area of interest. The area under the standard normal curve that lies between - 1 and 1 is (Type an integer or decimal rounded to four decimal places as needed.)

Find to.20 for T distribution with 29 degrees of freedom. to.20 (Round the answer to 3 decimal places)

Find the value of t for the t distribution for the following. Area in the right tail = 0.05 and df =12 Round your answer to 3 decimal places. T=

Fill in the rest of the joint distribution so that X and Y are independent. There are two possible answers: Y 0 1 X=0 1 ? 2/9 2/9

Find the value of t for the t distribution with a sample size of 30 and area in the right tail equal to 0.025 . Round your answer to 3 decimal places.