For a prism with an apex angle of 60° and an index of refraction of 1.56. If an incident ray enters the prism at 35° from the surface normal, how many degrees will the exiting light ray deviate? 0₁ 2) 8=0+0-a il 12 B Here are some formulas for your reference: 1)a=0₁₁+0 12 a α 02/ n - 3) 8=0,₁+ sin−¹[(sin a) (n² — sin² 0₁₁) ¹/²_ sin 0₁₁ cos a]- a il D (0₁1-0₁₁) 102 114 (02-012)

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