For a large population of people, the probability distribution for the random variable X = the number of meals a person ate yesterday and the assigned probabilities is given below: Meals, X Probability (a) Find P(X= 5), the probability that a randomly selected person ate 5 meals yesterday. P(X= 5) = 1 2 3 4 5 0.17 0.35 0.24 0.17 ? (b) Find P(X ≤ 2), the probability that a randomly selected person ate 2 or fewer meals yesterday. P(X ≤ 2) = (c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday. P = (d) Find P(X> 1), the probability that a randomly selected person ate more than 1 meal yesterday. P(X > 1) =

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For a large population of people, the probability distribution for the random variable \( X \) (the number of meals a person ate yesterday) and the assigned probabilities is given below:

| Meals, \( X \)    | 1   | 2   | 3   | 4   | 5   |
|-------------------|-----|-----|-----|-----|-----|
| Probability       | 0.17| 0.35| 0.24| 0.17| ?   |

### Questions

(a) Find \( P(X = 5) \), the probability that a randomly selected person ate 5 meals yesterday.  
\[ P(X = 5) = \_\_\_\_ \]

(b) Find \( P(X \leq 2) \), the probability that a randomly selected person ate 2 or fewer meals yesterday.  
\[ P(X \leq 2) = \_\_\_\_ \]

(c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday.  
\[ P = \_\_\_\_ \]

(d) Find \( P(X > 1) \), the probability that a randomly selected person ate more than 1 meal yesterday.  
\[ P(X > 1) = \_\_\_\_ \]
Transcribed Image Text:For a large population of people, the probability distribution for the random variable \( X \) (the number of meals a person ate yesterday) and the assigned probabilities is given below: | Meals, \( X \) | 1 | 2 | 3 | 4 | 5 | |-------------------|-----|-----|-----|-----|-----| | Probability | 0.17| 0.35| 0.24| 0.17| ? | ### Questions (a) Find \( P(X = 5) \), the probability that a randomly selected person ate 5 meals yesterday. \[ P(X = 5) = \_\_\_\_ \] (b) Find \( P(X \leq 2) \), the probability that a randomly selected person ate 2 or fewer meals yesterday. \[ P(X \leq 2) = \_\_\_\_ \] (c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday. \[ P = \_\_\_\_ \] (d) Find \( P(X > 1) \), the probability that a randomly selected person ate more than 1 meal yesterday. \[ P(X > 1) = \_\_\_\_ \]
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