For a given soil, the following are given: Gs = 2.67; moist unit weight,y= 112 lb/ft3; and moisture content, w = 10.8%. Determine:a. Dry unit weightb. Void ratioc. Porosityd. Degree of saturation For a given soil, the following are given: G, = 2.67; moist unit weight, y = 112 lb/ft’;and moisture content, w = 10.8%. Determine:a. Dry unit weightb. Void ratioc. Porosityd. Degree of saturation

Answered: Image /qna-images/answer/fbef85a2-6ae6-472b-9833-53353ea9b267.jpg

Answered: For a given soil, the following are…

For a given soil, the following are given: Gs = 2.67; moist unit weight,y= 112 lb/ft3; and moisture content, w = 10.8%. Determine: a. Dry unit weight b. Void ratio c. Porosity d. Degree of saturation

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A 100% saturated soil has a dry unit weight of 17.5kN/m³, and it's water content is 25%. Required:…

A: Given data:- Dry unit weights of 100% saturated soil is 17.5 kN/m3 Water content in soil is 25%

Q: 4. A clay sample has the following properties: • Porosity = 0.35 . Maximum void ratio = 0.85 .…

Q: Problem 4 For a given soil, the following are given: G₂ = 2.67; moist unit weight, y moisture…

Q: The water content of a 100% saturated soil is 30%, and the specific gravity of solids is 2.50.…

A: Water content = w = 30% Degree of saturation = S = 100% Specific gravity = G = 2.65 To determine -…

Q: A man collected a sample of soil outside of his house. The moist unit weight of the soil is 18.9 ,…

A: (a)

Q: The moist weight of 5.66 x 103 m³ of a soil is 102.3 x 103 kN. The moisture content and the specific…

Q: For an undisturbed soil, the total volume is 5.1 cubic feet, the moist weight is 601 pounds, the dry…

Q: The moist unit weight of a soil is 17.79 kN/cu.m and the porosity is 0.416. If the specific gravity…

Q: The total volume of a soil specimen is 80,000 mm3 and it weighs 150 grams. The dry weight of the…

A: Find the following: a) The water content. b) Void Ratio. e) Porosity. d) Degree of saturation. e)…

Q: st unit weight o sture content is of the soil solids

Q: For a given soil, show that 1 + W sat w Yw Ysat = n( = n(¹ Won)y. W sat where wsat = moisture…

A: Prove the given relation between different quantities.

Q: For a given soil, the following are given in Table: Specific Gravity Gs. bulk unit weight (Y), and…

A: Dry unit weight is a measure of the number of solid particles per unit volume. Void ratio is defined…

Q: A saturated soil sample has a water content of 63.0% and a specific gravity of soil solids of 2.61.…

A: Given, As the soil sample is already Saturated, Therefore the degree of saturation (s)= 100% , In…

Q: Problem For a given sol, the following are known, G, = 2.70, moist unit weight is 20.3067&N /m², and…

Q: For a soil, given: void ratio= 0.81, moisture content = 21%, and G, = 2.68. Calculate the following:…

Q: 3.8 When the moisture content of a soil is 26%, the degree of saturation is 72%, and the moist unit…

Q: 13. A soil has a specific gravity of solids (Gs) of 2.65, a water content of 13% and a void ratio of…

A: Porosity: Porosity is the measure of the void space in the material. The amount of void space is…

Q: The o weight of 0.1 cubic feet of soil is 12.2 Ib. If the moisture content is 12% and the specific…

A: Given data in question Volume 0.1 ft3 weight 12.2 lb Moisture content 12% Specific gravity 2.72 To…

Q: 3.16 The moist density of a soil is 1935 kg/m³. Given w = 18% and G, = 2.7, determine: a. Dry…

Q: Dry unit weight of a soil 16.5kN/m3 maximum dry unit weight 18.0kN/m3 the minimum dry unit weight…

Q: Q4: the moist unit weight of a soil is 19.2kN/m³. Given that Gs =2.69 and w=9.8%, determine a. Dry…

A: The given data is as follows: Moist unit weight of soil=19.2 kN/m3Gs=2.69w=9.8%

Q: 1. The moist weight of (2.7 + 0.25A) x 10° m³ of soil is (55.5 +0.1C) x 103 kN. If the moisture…

A: in the given question the suffix A,B,C and D are nothing but their own first characters value.…

Q: . Soil profile and properties of each layer are shown below, the water table is located 2.5m below…

A: NOTE:- as per our guidelines we are supposed to solve first three SUBPARTS only .please repost other…

Q: Q2- Classify the soil of following properties according to Unified and Textural Classification…

A: given: L.L=40%P.L=35%

Q: SUBJECT : SOIL MECHANICS The moist weight of 0.2 cubic ft of a soil is 23lbs the moisture content…

Q: 1. A SATURATED SOIL HAS THE FOLLOWING CHARACTERISTICS: INITIAL VOLUME = 19.65 CC., FINAL VOLUME =…

Q: 2. A saturated soil has the following characteristics: Initial Volume = 21 cc Final Volume = 16 cc…

A: Given data A saturated soil has the following characteristics: Initial Volume (V 1 )= 21cc Final…

Q: Compute the total unit weight, dry unit weight, water content, and saturated unit weight of the soil…

A: Compute the total unit weight, dry unit weight, water content, and saturated unit weight of the soil…

Q: A moist soil has a volume of 0.0081 m³ and weighs 151.2 N. The oven dry weight of soil is 138.6 N.…

A: Given: Volume of moist soilV=0.0081 m3 Weight of moist soilW=151.2 N Dry weight of soilWs=138.6 N…

Q: 4. For a given soil, the following are known: G, = 2.74, moist unit weight, y = 20.6 kN/m³, and…

A: Specific gravity, bulk density and water content has been given and it has been asked to determine…

Q: (b) On a partly saturated soil the following properties are know: e = 0.6 Gs = 2.75 S, = 70% Please…

A: Given data in question Void ratio Degree of saturation Specific gravity To find out water…

Q: Using Unified Soil Classification System, determine the type of soil, the coefficient of gradation…

A: To Find :- Type of Soil Coefficient of gradation Group symbol Given Passing no 4 = 47% Passing no…

Q: 3.3 The moist weight of 0.1 ft' of soil is 12.2 lb. If the moisture content is 12% and the specific…

Q: Determine the degree of saturation, Sr after dryin de the answer in % and the value must be round ;…

A: We know relationSe=wGS=Degree of saturationG=2.7 (constant )e=0.7(after drying)w=20%=0.2(after…

Q: 1- The moist unit weight of a soil is 20 kN/m3. Given that Gs = 2.7 and w = 9.5%, determine: ● Void…

A: Given that :- Moist unit weight of soil = γ =20 kN/m3 Gs=2.7w = 9.5% To determine a) void ratio b)…

Q: Determine the engineering properties of the following soil sample: the volume of the wet soil is 110…

Q: In its natural state a moist soil has a volume of 0.45 ft3 and weight of 51.32 lb. The oven-dry…

Q: The coefficient of gradation for certain soil is 4. Given that is D10 and D30 is 0.045 mm and 0.210…

Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

For a given soil, the following are given: Gs = 2.67; moist unit weight,y= 112 lb/ft3; and moisture content, w = 10.8%. Determine:
a. Dry unit weight
b. Void ratio
c. Porosity
d. Degree of saturation

For a given soil, the following are given: G, = 2.67; moist unit weight, y = 112 lb/ft’;
and moisture content, w = 10.8%. Determine:
a. Dry unit weight
b. Void ratio
c. Porosity
d. Degree of saturation

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

7
A sample of saturated soft clay has a moisture content of w. The specific weight of solids é ys em g-f/cm' (Table 1). What is the void index, porosity and saturated specific weight of the soil (in g-f/cm). Adopt water specific weight of 1 g-f/cm3.
3) For a given moist soil, given that volume = 33m3; mass = 33kg; moisture content = 10%; Gs = 2.7, calculate the following: a. Moist density (kg/m3) b. Dry density (kg/m3) c. Void ratio d. Porosity e. Degree of saturation (%) f. Volume occupied by water
A sample of fully saturated clay weighs 2.98 pounds in its natural state and 2.15 poundsafter drying. Determine the following:a. Natural water contentb. Void ratioc. Porosityd. Moist densitye. Dry density (Hand written please)
2.) The unit weight of soil is 15.1kN/m3. The moisture content of this soil is 17% when the degree of saturation is 60%. Determine the: -void ration -Sp.gr. of soil -Saturated unit weight
For soil in natural state, given e - 0.8, w=24%, and Gs = 2.68. (a) Determine the bulk unit weight, dry unit weight, and degree of saturation. (b) If the soil is made completely saturated by adding water, what would its moisture content be at that time? Also find the saturated unit weight.
Q2) Classify a soil using USCS from the following information: 75% of the material is retained on the sieve No.200. less than of the percent above and more than 50%, is passing on the sieve No.4. L.L. 35% and P.L.= 29% D10 0.18mm, D30 = 0.88mm, and D60 = 1.12mm d)
Q2- Classify the soil of following properties according to Unified and Textural Classification Systems; L.L= 40% P.L = 35% (show all calculations and steps). Size, mm 0.212 0.15 0.075 0.02 0.006 0.004 0.001 % finer 100 89 (50+N) 47 38 30 (5+N) N=5
Show solution 2