For a coin that is dropped at the top of the building, compare the potential energy at the bottom and the kinetic energy at top (air resistance is present) OK>U Not enough information OK-U OK

One model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r)=U0[(r0/r)12−(r0/r)4] where r0 = 0.65 nm and U0 = 7.4 eV.Note: 1 eV = 1.6×10−19 J.Some helpful units:[Force] = eV/nm[Energy] = eV[distance] = nm Here is what I am having trouble with: You can choose where the potential energy equals zero anywhere you want (you can add or subtract any constant to it). For this function, U(∞) = 0. This is very common for electromagnetic problems like you will see in Physics 2. If the potential energy function were defined as U(r)=U0[(r0/r)12−(r0/r)4]+U1 where U1 = 4.5 eV, reanswer all of the previous questions using this new potential energy function. req= ? Fr(req+r1)= ? K(req)= ? (NOTE: these are all part of the same question) I got .957026 nm for req, and -1.4348 eV/nm for Fr(req+r1), and I couldnt get an answer for K(req). My answers are wrong. Where am I not understanding?

A student evaluates a weight loss program by calculating the number of times he would need to climb a 16.0 m high flight of steps in order to lose one pound (0.45 kg) of fat. Metabolizing 1.00 kg of fat can release 3.77 x 10 J of chemical energy and the body can convert about 21.8% of this into mechanical energy (the rest goes into internal energy.) HINT (a) How much mechanical energy (in J) can the body produce from 0.450 kg of fat? (b) How many trips up the flight of steps are required for the 66.0 kg student to lose 0.450 kg of fat? Ignore the relatively small amount of energy required to return down the stairs. trips Need Help? Read It Watch It

Can u please show the math (step 5) step by step for this question? I would deeply appreciate it .