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- About _________% of the area under the curve of the standard normal distribution is between z=−0.928z=-0.928 and z=0.928z=0.928 (or within 0.928 standard deviations of the mean).A water footprint is a measure of the appropriation of fresh water. The per capita water footprint (in mega gallons) in a certain country for a recent year can be approximated by a normal distribution, as shown in the figure. Population mean, µ = 1.66 Mgal Population standard deviation, σ = 2.85 Mgal (a) What water footprint represents the 80th percentile? (b) What water footprint represents the 30 th percentile? (c) What water footprint represents the third quartile?1. A normal distribution of scores has a standard deviation of 10 and a mean of 50. Find the z-scores and its area under the normal curve corresponding to each of the following values: a. A score that is 20 points above the mean. b. A score that is 10 points below the mean.
- Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV1. Assume the mean FEV1 for 10-year-old boys is 2.1 liters and that the population standard deviation is =σ0.5 . A random sample of 7010-year-old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV1 of 2.03 liters. Can you conclude that the mean FEV1 in the high-pollution community is less than 2.1 liters? Use the =α0.05 level of significance and the P-value method with the TI-84 calculator.Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called the forced expiratory volume in one second, and is abbreviated FEV,. Assume the mean FEV, for 10-year-old boys is 2.1 liters and that the population standard deviation is o = 0.4. A random sample of 78 10-year-old boys who live in a community with high levels of ozone pollution is found to have a sample mean FEV, of 2.07 liters. Can you conclude that the mean FEV, in the high-pollution community differs from 2.1 liters? Use the a = 0.10 level of significance and the critical value method with the table. Part: 0 / 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. OPulmonary Disease Forced expiratory volume (FEV) is an index of pulmonary function that measures the volume of air expelled after 1 second of constant effort. FEV is influenced by age, sex, and cigarette smoking. Assume that in 45- to 54-year-old nonsmoking men FEV is normally distributed with mean = 4.1 L and standard deviation = 0.5 L. = 0.6 L. (Assume that FEV can be measured exactly and no continuity correction is In comparably aged currently smoking men FEV is normally distributed, with mean = 3.9 L and standard deviation necessary. Round your answers to four decimal places.) USE SALT (a) If an FEV of less than 2.5 L is regarded as showing some functional impairment (occasional breathlessness, inability to climb stairs, etc.), then what is the probability that a currently smoking man has functional impairment? (b) What is the probability that a currently nonsmoking man has functional impairment? Some people are not functionally impaired now, but their pulmonary function usually…About ___________% of the area under the curve of the standard normal distribution is between z=−0.145z=-0.145 and z=0.145z=0.145 (or within 0.145 standard deviations of the mean). About __________% of the area under the curve of the standard normal distribution is outside the interval z=[−1.48,1.48]z=[-1.48,1.48] (or beyond 1.48 standard deviations of the mean). About________ % of the area under the curve of the standard normal distribution is outside the interval z=−1.82z=-1.82 and z=1.82z=1.82 (or more than 1.82 standard deviations from the mean).Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV1. Assume the mean FEV1 for 10 -year-old boys is 2.1 liters and that the population standard deviation is =σ0.4 . A random sample of 35 10 -year-old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV1 of 1.98 liters. Can you conclude that the mean FEV1 in the high-pollution community differs from 2.1 liters? Use the =α0.10 level of significance and the P -value method with the TI-84 calculator. Part: 0 / 4 0 of 4 Parts Complete Part 1 of 4 State the appropriate null and alternate hypotheses. :H0 :H1 This hypothesis test is a ▼(Choose one) test.mean = 50 standard deviation=6 p(48<X<70)Tire lifetimes: The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean u = 12.08 and standard deviation o = 00 0.01. Round the answers to at least three decimal places. (a) Find the 10" percentile of the tire lifetimes. (b) Find the 2nd percentile of the tire lifetimes. (c) Between what two values are the middle 80% of the tire lifetimes?About ____% of the area under the curve of the standard normal distribution is between z=−0.106z=-0.106 and z=0.106z=0.106 (or within 0.106 standard deviations of the mean). About ____% of the area under the curve of the standard normal distribution is between z=−0.768z=-0.768 and z=0.768z=0.768 (or within 0.768 standard deviations of the mean).A normal distribution has a mean ofu = 58 and a standard deviation of o = 12. Standard Normal Distribution Mean = 0.0 Standard Deviation = 1.0 5000 5000 -3 -2 -1 1 0.0000SEE MORE QUESTIONS