following table contains observed frequencies for a sample of 200 .     Column Variable     Row Variable A B C P 20 46 40 Q 30 24 40   Test for independence of the row and column variables using a=.05. Compute the value of the X^2  test statistic (to 2 decimals).     The p-value is _____

Given below are the analysis of variance results from a stat software display comparing sample data for the meanmileage for 4 different types of cars. Assume that you want to use a 0.05 significance level in testing the null hypothesisthat the different samples come from cars with the same mileage. What can you conclude about the equality of the population means?Source DF SS MS F pFactor 3 13.500 4.500 5.17 0.011Error 16 13.925 0.870Total 19 27.425 12)What is the null and alternative hypothesis for this scenari?Based on this One Way Anova software analysis, would you reject of fail to reject the nul hypothesis?What does this result mean in context?

The average house has 13 paintings on its walls.  Is the mean different for houses owned by teachers? The data show the results of a survey of 12 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 12, 14, 14, 14, 15, 14, 14, 14, 12, 13, 15, 14 What can be concluded at the  αα = 0.01 level of significance? For this study, we should use     The null and alternative hypotheses would be:       H0:H0:                   H1:H1:               The test statistic     =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is     αα Based on this, we should      the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 13 at αα = 0.01, so there is sufficient evidence to conclude that the population mean number of paintings that are in teachers' houses is equal to 13. The data…

You intend to conduct a test of independence for a con tingency table with 4 categories in the column variable and 6 categories in the row variable. You collect data from 595 subjects. What are the degrees of freedom for the x distribution for this test? d.f. =

An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). If answer is zero enter "0". Source Sum Degrees Mean of Variation of Squares of Freedom Square F p-value Treatments 800 3 Blocks 600 7 Error 300 21 Total 1700 31 Use a = 0.05 to test for any significant differences. The p-value is - Select your answer What is your conclusion? - Select your answer -

Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level).   One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p             Between-group (treatment) 2   469.1827 2677.864 2.30 0.104 Within-group (error)       118    203.6918 11745.05     Total       120