Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 10.5 1 CN Pa

Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 10.5 1 CN Pa

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter7: Permeability

Section: Chapter Questions

Problem 7.20P

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Q9) The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 31 cm Length of sample = 98 cm Constant head difference = 52 cm Time of collection = 364 secs Weight of water collected = 448 grams Find the seepage velocity in cm/min. if the void ratio is 0.33. Round off to four decimal places.
The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 31 cm Length of sample = 98 cm Constant head difference = 52 cm Time of collection = 364 secs Weight of water collected = 448 grams Find the seepage velocity in cm/min. if the void ratio is 0.33. Round off to four decimal places. Answer: 0.3943
The standard penetration test results of a sand deposit at a certain site are given below in tabular form. The groundwater table in located at a depth of 2 m below the ground surface. The dry and saturated unit weights of sand are 17 kN/m³ and 19.0 kN/m', respectively. For an expected 10.8 earthquake magnitude M = 6 and maximum acceleration amax = 0.1 g, will liquefaction occur? Depth (m) NF (blows/30 cm) 1.5 8 3.0 7 4.5 12 6.0 15 7.5 17 9.0 17
A standard penetration test is carried out in sand where the efficiency of the hammer nH =70%. If the measured N-value at 30 ft depth is 24, find N60 and (N1)60. The unit weight of the sand is 115.0 lb/ft3. Assume nB = nS = nR =1.
Question 16 The results of a constant head permeability test for a fine sand are as follows Diameter of the sample = 33 cm Length of sample 55 cm Constant head difference =74 cm Time of collection 580 secs Weight of water collected = 382 grams Find the seepage velocity in cm/min. if the void ratio is 0 38. Round off to four decimal places. SUS WE R
Question 40 The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 25 cm Length of sample = 80 cm Constant head difference = 77 cm Time of collection = 388 secs Weight of water collected = 340 grams Find the seepage velocity in cm/min. if the void ratio is 0.49. Round off to four decimal places.
(b) The results of a constant head permeability test for a fine sand having a diameter of 90 mm and a length of 160 mm are given as follow. Determine constant head difference water collected in 7 min void ratio of sand = 580 mm = 470 cm³ = 0.8 (i) Hydraulic conductivity in, k in (cm/sec). (ii) Seepage velocity.
P-1 A soil profile is shown in Figure along with the standard penetration numbers in the clay layer. Use provided equations to Dry sand y = 16.5 kN/m³ 1.5 m Groundwater table Sand 1.5 m N60 Ysat = 19 kN/m³ determine the variation of 1.5 m • 8 Cu and OCR and preconsolidation pressure o', with depth. What is the average value of c, and OCR? Clay 1.5 m Ysat = 16.8 kN/m³ * A•8 1.5 m • 9 1.5 m 10 Sand 0.689 0.29N0.72 Pa Си N60 OCR = 0.193 o = 0.47NPa %3D %3D Shahid Chamran University of Abvaz 1 ר ר ררפ
16. For a constant laboratory permeability test on a fine sand, the following data are given: Length of specimen: 16 cm. Diameter of specimen: 97 mm. Constant head difference: 51 cm. Volume of water collected in 5.96 min.: 422 cc Void ratio of the soil specimen: 0.58 Determine the seepage velocity in m/min. Round off to four decimal places.
A dilatometer test was conducted in a clay deposit. The groundwater table was locatedat a depth of 3 m below the surface. At a depth of 8 m below the surface, the contact pressure spod was 280 kN/m2 and the expansion stress sp1d was 350 kN/m2. Determinethe following:a. Coefficient of at-rest earth pressure, Kob. Overconsolidation ratio, OCRc. Modulus of elasticity, EsAssume s 9o at a depth of 8 m to be 95 kN/m2 and ms 5 0.35.
HYDRAULIC CONDUCTIVITY PROBLEM 1: The results of a constant head permeability test for a fine sand and sample having a diameter of 150 mm and a length of 150 mm are as follows: Constant head difference = 40 cm Time of collection of water = 83 sec Weight of water collected = 392 g Find the hydraulic conductivity a. 0.094 cm/sec b. 0.01 cm/sec C. c. 0.005 cm/sec d. 0.86 cm/sec
3. From constant head permeability test on fine sand, the following data were recorded: Length of sample = 16 cm Diameter of sample = 9.6 cm Constant head difference = 50 cm Volume of water collected in 4 minutes = 420 cm³ a. Determine the coefficient of permeability in cm/sec. b. Find the discharge velocity in cm/sec. c. If the void ratio is 0.55, compute the seepage velocity in cm/sec.