Following are the perpendicular offsets that were taken from a chain survey: Change (m) 30 60 90 120 150 180 210 Offset length (m) 8.76 7.89 9.43 8.44 7.54 7.35 8.75 The area enclosed by the chain line and irregular boundary by Trapezoidal rule is m2.

Following are the perpendicular offsets that were taken from a chain survey: Change (m) 30 60 90 120 150 180 210 Offset length (m) 8.76 7.89 9.43 8.44 7.54 7.35 8.75 The area enclosed by the chain line and irregular boundary by Trapezoidal rule is m2.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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An irregular lot was surveyed to obtain its area. Compute for the lot’s area using DPD method. (Balance the traverse using the Compass Rule). The obtained data are as follows:
FUNDAMENTALS OF SURVEYING 1 All azimuths are measured from South. All angles must be written to the nearest minute only. All latitudes and departures must be written to two decimal places only. 3.The algebraic sum of latitude and departure of a six-sided tract of land are as follows: EL = - 1.35m, precision or relative error of the survey. ED = + 1.18 m. If the total length of boundary is 455. 56m, determine the 4.The latitude and departure of a traverse line were computed as +77.56m and – 87.78m respectively. a) Determine its bearing b) Determine azimuth, c) Determine is distance.
it said i got 1 item wrong. im so confused now. where did i go wrong? (btw this is only a activity for us to practice but i still don't get it)
A clockwise traverse ABCDEA was surveyed Find the length and direction of line AD Line AB BC CD DA Length(m) 101.01 140.24 99.27 C B D A E Direction 00°00'00" 77°55'30" 173°37'20" D D 137.137 11.027 L sine L 101.01 29.337 -98.656 L cose AD=151.515m,0=257°55′37" O AD=144.735m,0=77°55′37″ O AD=151.515m,0=77°55′37" O AD=145.735m,0=257°55'37" AD=144.735m,9=257°55′37″ O
Use DMD & DPD Method to calculate the Area of the closed traverse whose data is given below. Draw the figure. LINE CORRECTED DEPARTURE CORRECTED DISTANCE 413.53341 596.41168 AB CORRECTED LATITUDE +296.42872 - 246.85339 + 104.50281 154.07815 + 288.33990 BC CD +542.92753 - 597.93576 - 233.33167 606.99919 DA 279.61356
A clockwise traverse ABCDEA was surveyed Find the length and direction of line AD Line AB BC CD DA Length(m) 101.01 140.24 99.27 C B D A E Direction 00°00'00" 77°55'30" 173°37'20" D D 137.137 11.027 L sine L 101.01 29.337 -98.656 L cose AD=151.515m,0=257°55′37" O AD=144.735m,0=77°55′37″ O AD=151.515m,0=77°55′37" O AD=145.735m,0=257°55'37" AD=144.735m,9=257°55′37″ O
3. A and B are two points located on each bank of a river and near the abutments of a proposed bridge. To determine its distance, a baseline CD 180 m long was established on one bank of the river and the transit was set up at stations C and D and the azimuth were taken as follows: Azimuth LINE (degrees) 210°00' С - D C - A 260°00' 290°00' С -В D - A D - B 301°00' 315°00' 1. Find the distance AD.
2. The following offsets, with Sm interval were measured at right angles from a traverse line to inegular boundaries. Calculates the area between the traverse line and the irregular boundaries using the trapezoidal rule and Simpson rule. CH 16 24 32 40 48 56 64 72 RL(m) 0 15.2 14.8 13.5 14.2 15.2 15.6 15.8 16.2
Offset Point A� B� C� D� E� F� G� Stationing 0.00 0 + 54.80 1 + 34.44 2 + 13.02 2 + 98.74 3 + 43.8 4 + 50.17 Offset 13.2 34.2 54.7 85.4 67.9 68.9 23.8 Compute the area between a lake and a straight line AG��, from which offsets are taken at irregular intervals as shown in the table above (all distances in feet). Express your answer in feet squared to four significant figures. Activate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value type areaarea = = ft2
Determine the coordinates of points A,B,C,D and E. Distances between the points are given below. |14| = 21.643 m |AB| = 48.413 m |BC| = 57.743 m |CD| = 40. 722 m |DE| = 19.682 m E 226.7001g x=191.134 m 133.5995g y=24.920 m 1 138.2277g B 170.9221g D A
The following perpendicular offsets were taken from a survey distance (m) 0 55 5 70 10 15 30 40 20 Offset (m) 3.92 4.32 3.29 4.05 5.26 2.91 4.76 6.23 5.75 Compute the area between the survey line and an irregular boundary using trapezoidal rule or Simpson's rule. 3 line.