FNT 13-1 Vectors F EF = 0 F3 on object =? Fr on object =? on object, F2 on object, F3 on object, and F4 on object are all exerted on an object, adding together to form a net force vector EF = 0, as shown to the right. However, only vectors Fi on object, Ēzem-object- on object F2 on object, and EF (which is zero) are It is known that F3 on object object known. is completely vertical, and F4 on object pletely horizontal. is com- On a separate piece of graph paper, use the properties of vector addition to determine the magnitudes of the vertical vector F3 on object, and the horizontal vector F4 on object.

How to find the average force when only given two distances and two forces. Distance = 0m & 0.01m Force= 0N & 1.20N

I1= 5A, I2= 0.7A, a=.03m. b=.11m, d=.18m a.) Find FAD magnitude and direction b.) Find FBC magnitude and direction c.) Find Net Force on ABCD magnitude and direction.

Calculating Net Force Two forces act on an object: 1) a force of magnitude F₁ and direction 0₁ 2) a force of magnitude F2 and direction 02 The net force on the object has a magnitude of Fnet and a direction of Onet. Solution: Forces must be added in component form (x and y separately): Fnet,x=F₁ cos 0₁ + F₂ cos 0₂ = Fnet CoS Onet Fnet.y Fnet sin net The 2 equations above have 6 variables. So if 4 variables are given, the equations can be solved. Tip: Plug in decimals for sines/cosines of known angles. = · F₁ sin 0₁ + F2 sin 0₂ = 3 4 F₁ 184N 305.6 F₁ N Type your answer... 0₁ 170⁰ 0₁ 156⁰ F₂ 349N F₂ 336N 02 289⁰ 02 301⁰ Fnet N Onet 244⁰ --DO