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- For the magnetic circuit shown in the figure, the iron core with N = 500 turns -Magnetic permeability is 200. its average length is 40 cm -The diameter of the cross-sectional area is 1 cm. Find the current that must pass through the winding to produce 0.5 mWb of flux in a 1mm air-gap magnetic circuit?Example(6): A magnetic circuit containing an air gap is shown in Figure below. With the dimension as marked, calculate the current in the coil to establish a flux density of 0.6 T in the air gap. The core has the B - H characteristics. Repeat above but correct for fringing and lamination. Consider SF=0.95, FF 1.08 while is as above. 2 mm) A-5cm²Consider a ferromagnetic ring (nucleus) that has a mean circumference of 40 cm, 300coiled copper turns and a sectional area of 5 cm2. A current of 2 is appliedA to winding, producing a flux of 1.5 mWb.Determine the permeability of the core material.Determine the relative permeability of the core material.If the ferromagnetic ring has an air gap of 2 mm. Find the required MMFso that the flux density in the gap is 0.5 T.
- A three-legged ferromagnetic magnetic core with the coil dimensions shown below has a of 500 turns wrapped around the right leg. The core relative permeability is 4000 times, The magnetic flux in the left leg of the core has a value of 40 mWb. The center leg has an air gap of 0.8 mm, its fringing effect is neglected. Draw the corresponding magnetic circuit and find the values of the coil current i, and the flux in each leg of the core. cm 10 cm, 25cm 25 cm 10 cm 10 cm 25 cm 0.8 mm 500 turns 10 cm Core depth = 10 cm(a) Explain briefly what is fringing effect and leakage flux. (b) A ferromagnetic core is shown in Figure 1. The depth of the core is 10 cm. The other dimensions of the core are as shown in the figure. By assuming the magnetic leakage to be negligible and relative permeability of the core is 800. Calculate the total reluctance and find the value of the current that will produce a flux of 0.01 Wb. With this current, calculate the flux density at the top of the core 20 cm 40 cm 10 cm, 30 cm 500 turns 30 cm 30 cm Figure 1A biped magnetic core (core) is shown in the figure. The coil on the left leg of this core (N1) has 400 turns and. the right (N2) winding has 300 turns. Coils are wound in the directions shown in the figure. The core depth is (15 cm) and the dimensions of the core are as shown in the figure How much flux (@=?) is produced by coil currents İ1 = 5 A and 12 = 10 A Assume ur = 1000 and constant Please I want the answer step by step. 50 cm * 15 cm 50 cm 15 cm 15 cm- 400 turns N₁ 300 turns N₂ 15 cm- ½ Core depth = 15 cm
- A ferromagnetic core is shown in Figure Pl-2. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.005 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 800. 1-5. 10 cm- 5em 20 em 15 cm 15 cm 15 cm Coe depth - Scm SOLUTION There are three regions in this core. The top and bottom form one region, the left side forms a second region, and the right side forms a third region. If we assume that the mean path length of the flux is in the center of each leg of the core, and if we ignore spreading at the corners of the core, then the path lengths are I, = 2(27.5 cm) = 55 cm, I, = 30 cm, and /, = 30 cm. The reluctances of these regions are:Figure 1 shows a ring formed with two different materials – cast steel and mild steel. Mild steel has a mean length of 400 mm and an area of 500 mm². Cast steel has a mean length of 300 mm and an area of 312.5 mm2. The magnetisation curve for mild steel and cast steel is shown in Figure 2. Find the total MMF required to cause a flux of 500 µWb in the magnetic circuit. Determine also the total circuit reluctance. 1.8 Cașt steel Cast-steel 1.6 Silicon iron 1.4 Mild steel 1.2 1.0 0.6 Mild stel Cast iron 0.6 Figure 1: Ring arrangement 0.4 0.2 3000 4000 Magnetic field strength, H(A/m) 1000 2000 5000 600ỘI 7000 Figure 2: Magnetization Curve MMF = AT Reluctance = x 10* ΑT/Wb Flux density, B(T)A ferromagnetic core is shown in Figure PI-2. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.005 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 1000. -10 cm- - 20 cm- 15 cm 400 turns 15 cm 15 cm Core depth 5 cm
- A toroidal core with a mean circumference of 100 cm and a cross sectional area of 10 cm² is wound with 500 turns of wire. What current would be required to generate a flux of 1 mWb in the core. Assume the core has a relative permeability of 800. a. 1 A b. 2 A c. 1.5 A d. 2.5 AQUESTION 1 A ferromagnetic core is shown in Figure 1. The depth of the core (in to page) is 15cm, and the other dimensions are shown in the figure. There is a 150-turn coil wrapped around the left side of the core with input current is 2 Ā. a) Draw and label a magnetic circuit of ferromagnetic core below b) Assuming relative permeability, pr of 2400,calculate: i. Total reluctance ii. Magnetomotive force of the circuit Total flux of the circuit ii. 15cm 20cm 15cm 15сm N= 150 20cm 15cm 15cm 20cm 15cm Figure 1: Ferromagnetic CoreA ferromagnetic core with a relative permeability of 1500 is shown in the following figure. The depth of the core is 5 cm. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core, and if the current in the coil is 1.25 A, find the magnetic flux and the field density in all three legs of the core, as well as the magnetic flux and flux density in the two air gaps.