
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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![### Probability Distribution: X-linked Genetic Disorder
#### Problem Description
Five males with an X-linked genetic disorder each have one child. The random variable \( x \) represents the number of children, among the five, who inherit the disorder. Determine if the table represents a probability distribution, and if so, calculate the mean and standard deviation. If not, identify the failed requirements.
#### Data Table
| \( x \) | \( P(x) \) |
|--------|------------|
| 0 | 0.032 |
| 1 | 0.146 |
| 2 | 0.322 |
| 3 | 0.322 |
| 4 | 0.146 |
| 5 | 0.032 |
#### Questions
1. **Does the table show a probability distribution?** Select all that apply:
- [ ] A. Yes, the table shows a probability distribution.
- [ ] B. No, the random variable \( x \)'s numbers are not associated with probabilities.
- [ ] C. No, not every probability is between 0 and 1 inclusive.
- [ ] D. No, the random variable \( x \) is categorical instead of numerical.
- [ ] E. No, the sum of all probabilities is not equal to 1.
2. **Find the mean of the random variable \( x \):**
- [ ] A. \(\mu =\) _______ child(ren) (Round to one decimal place as needed.)
- [ ] B. The table does not show a probability distribution.
3. **Find the standard deviation of the random variable \( x \):**
- [ ] A. \(\sigma =\) _______ child(ren) (Round to one decimal place as needed.)
- [ ] B. The table does not show a probability distribution.
#### Analyzing the Distribution
- **Probability Criteria:**
- Each probability should be between 0 and 1.
- The sum of all probabilities should be equal to 1.
- **Mean (\(\mu\)):**
The mean (\(\mu\)) of a probability distribution is calculated as:
\[
\mu = \sum [x \times P(x)]
\]
- **Standard Deviation (\(\sigma\)):**
The standard deviation (\(\sigma](https://content.bartleby.com/qna-images/question/7038cbde-5259-4f1b-ade8-fa8f6320a6eb/080eba8b-c359-4516-8015-e5774c43a537/omljqmw_thumbnail.png)
Transcribed Image Text:### Probability Distribution: X-linked Genetic Disorder
#### Problem Description
Five males with an X-linked genetic disorder each have one child. The random variable \( x \) represents the number of children, among the five, who inherit the disorder. Determine if the table represents a probability distribution, and if so, calculate the mean and standard deviation. If not, identify the failed requirements.
#### Data Table
| \( x \) | \( P(x) \) |
|--------|------------|
| 0 | 0.032 |
| 1 | 0.146 |
| 2 | 0.322 |
| 3 | 0.322 |
| 4 | 0.146 |
| 5 | 0.032 |
#### Questions
1. **Does the table show a probability distribution?** Select all that apply:
- [ ] A. Yes, the table shows a probability distribution.
- [ ] B. No, the random variable \( x \)'s numbers are not associated with probabilities.
- [ ] C. No, not every probability is between 0 and 1 inclusive.
- [ ] D. No, the random variable \( x \) is categorical instead of numerical.
- [ ] E. No, the sum of all probabilities is not equal to 1.
2. **Find the mean of the random variable \( x \):**
- [ ] A. \(\mu =\) _______ child(ren) (Round to one decimal place as needed.)
- [ ] B. The table does not show a probability distribution.
3. **Find the standard deviation of the random variable \( x \):**
- [ ] A. \(\sigma =\) _______ child(ren) (Round to one decimal place as needed.)
- [ ] B. The table does not show a probability distribution.
#### Analyzing the Distribution
- **Probability Criteria:**
- Each probability should be between 0 and 1.
- The sum of all probabilities should be equal to 1.
- **Mean (\(\mu\)):**
The mean (\(\mu\)) of a probability distribution is calculated as:
\[
\mu = \sum [x \times P(x)]
\]
- **Standard Deviation (\(\sigma\)):**
The standard deviation (\(\sigma
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