fine the are under the standard normal curve to the left of z= -0.94

Find the area below the standard normal curve to the right of z = 0.12.   A. 0.452   B. 0.548   C. 0.421   D. 0.210

Find the z value such that 97% of the standard normal curve lies between −z and z.

Find z such that 56% of the standard normal curve lies between −z and z. (Round your answer to two decimal places.

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. 2= -0.81 z=1.21 The area of the shaded region is (Round to four decimal places as needed.)

sketch the areas under the standard normal curve and find the specified areas: to the left z = -1.32 to the right of z = 0.48 to the right of z = 1.52 between z = 0 and z = 1.67 between z = 1.40 and z = 1.00