Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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the first one i ask here says it is wrong so, i asked again

**Problem:**

Find \( y' \) and \( y'' \) for the equation \( x^2 + 2xy - 3y^2 = 41 \). Simplify.

**Solution:**

For \( y' \):
- Derivative of the given equation with respect to \( x \) yields:

\[
y' = \frac{-2x - 2y}{2x - 6y}
\]

**Note:** There are links or buttons labeled "help (formulas)" that suggest assistance is available for formulas.

For \( y'' \):
- The second derivative \( y'' \) is not provided in the image, indicating a new calculation or formula is required.

**Assistance:**
- There are "help (formulas)" links suggesting additional resources or guides are available to assist with finding the derivatives.
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Transcribed Image Text:**Problem:** Find \( y' \) and \( y'' \) for the equation \( x^2 + 2xy - 3y^2 = 41 \). Simplify. **Solution:** For \( y' \): - Derivative of the given equation with respect to \( x \) yields: \[ y' = \frac{-2x - 2y}{2x - 6y} \] **Note:** There are links or buttons labeled "help (formulas)" that suggest assistance is available for formulas. For \( y'' \): - The second derivative \( y'' \) is not provided in the image, indicating a new calculation or formula is required. **Assistance:** - There are "help (formulas)" links suggesting additional resources or guides are available to assist with finding the derivatives.
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