Find y . 4 for the following function In (xx2+,

Match these values of r with the accompanying scatterplots: 1, -0.355, -0.718, 0.355, and 0.996. Scatterplot 1 Scatterplot 2 8- 6- 6- FUUS 4- 2-* 0- 0 0.2 0.4 0.6 0.8 1 X 4- 2- 0- 0 0.2 0.4 0.6 0.8 X > 15- 14- 13- 12- 11- Scatterplot 3 10+ . 0 0.2 0.4 0.6 0.8 X O A. Scatterplot 1, r=-0.355; Scatterplot 2, r = 1, Scatterplot 3, r = 0.355, Scatterplot 4, r = -0.718, Scatterplot 5, r = 0.996 B. Scatterplot 1, r = 0.355; Scatterplot 2, r = 0.996, Scatterplot 3, r = -0.355, Scatterplot 4, r = -0.718, Scatterplot 5, r = 1 O C. Scatterplot 1, r=-0.355; Scatterplot 2, r = 0.996, Scatterplot 3, r = 0.355, Scatterplot 4, r = -0.718, Scatterplot 5, r = 1 O D. Scatterplot 1, r= 0.355; Scatterplot 2, r = 1, Scatterplot 3, r = -0.355, Scatterplot 4, r = -0.718, Scatterplot 5, r = 0.996 8- 6- 4- 2- Scatterplot 4 0- 0 0.2 0.4 0.6 0.8 X 8- 6- 4- 2- 04 0 Scatterplot 5 . • 0.2 0.4 0.6 0.8 X ..

Consider the following model to grow simple networks. At time t = 1 we start with a complete network with no = 6 nodes. At each time step t > 1 a new node is added to the network. The node arrives together with m = 2 new links, which are connected to m = 2 different nodes already present in the network. The probability II, that a new link is connected to node i is: N(t-1) II¿ = ki - 1 Ꮓ with Z=(k-1) j=1 where ki is the degree of node i, and N(t - 1) is the number of nodes in the network at timet - 1.

Enter the appropriate number in each blank. - 1, if x -2 5x - f(x) : || X – 9, а. f(—4) — b. f(-3) = c. f(-2) = с. d. f(0) = Submit