Find x so that the triangle with vertices A(-7, 10, 8), B(-5, 2, 2), and C(-4, 9, x) has a right angle at A.

Find the area of the parallelogram with vertices at (5, –2), (11, 3), (14, –8), and (20, -3). Area = To submit: show your work

Find the area of the triangle with vertices: Q(0,2,-2), R(-1,3,-5), S(-3,-1,-8).

The points (3, 0), (-1, 1), (5, 1) and (1, 2) are the vertices of a parallelogram ABC D. If ABCD is translated by v = (3, –2), find the vertices of the new parallelogram A' B'C' D' . (Express numbers in exact form. Use symbolic notation and fractions where needed. Give your answer in the form of an unordered list of points (*, *), ... ,(*, *).) vertices of A' B'C' D':

Find the area of the parallelogram with vertices at (3, -3), (11, 1), (12, – 5), and (20, -1). Area

Show that the points A(-4,9,6) ,B(-1,6,6) and C (0,7,10) from the right angled isoseles triangle

Find the angles of the triangle with vertices: (0,1,0), (1,0,3) and (5,5,0)

Whats the area of a triangle if its vertices are at A (-8,-6), B (6,9) and C (8,-14)

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