Find the z score that has 78.5% of the distribution area to its right

Thanks. Why is Kathy's score considered better-is it because it is a posituve score? What does the Z score represent in this case?

Describe how would use a calculator and Statcruch to find Area to the Right corresponding a Z score.

Please round it to 4 decimal places and add the excel formulas as well.

What is the name of the test used?

Find the area of the shaded region. The graph to the right depicts IQ scores of​ adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.         A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, one on the left side and one on the right side. The region between the lines is shaded. Moving from left to right, the x-axis below the first line is labeled 75. The x-axis below the second line is labeled 110.

What does the P-value describe?

Today, the waves are crashing onto the beach every 4.4 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.4 seconds. Round to 4 decimal places where possible.

The largest error occurs when p =

The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do twenty year-olds have fewer cavities? The data show the results of a survey of 15 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 3, 4, 4, 4, 5, 5, 6, 4, 5, 4, 3, 5, 6, 5, 3 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v|| Select an answer H: ?v Select an answer v c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly less than 5 at o =- 0.05, so there is sufficient evidence to conclude that the population mean number of cavities for…