Find the z-score such that the area under the standard normal curve to the left is 0.46. is the z-score such that the area under the curve to the left is 0.46. (Round to two decimal places needed ) as

Find the z-score such that the area under the standard normal curve to the left is 0.49.

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.z=−0.93z=1.23  A symmetric bell-shaped curve is plotted over a horizontal scale. Two vertical lines run from the scale to the curve at labeled coordinates “z equals negative 0.93,” which is to the left of the curve’s center and peak, and “z equals 1.23,” which is to the right of the curve’s center and peak. The area under the curve between the vertical lines is shaded.Question content area bottomPart 1The area of the shaded region is enter your response here.​(Round to four decimal places as​ needed.)

Determine the area under the standard normal curve that lies between z=-1.50 and z=1.50. [Please write you answer as a whole  percentage]

What percentage of the area under the normal curve is between the following z-scores? Z1= -2.39 Z2= 1.03

Find the area under the standard normal curve between z = -2.49 and z = 1.38, P(-2.49 < z < 1.38). (Give your answer correct to four decimal places.)   Please give details. Thank you.

Find the​ Z-score such that the area under the standard normal curve to the left is 0.52.

Determine the area under the standard normal curve that lies to the left of (a) Z=1.39, (b) Z=0.54, (c) Z=-0.66, and (d) Z= -0.27. Click the icon to view a table of areas under the normal curve. (a) The area to the left of Z= 1.39 is (Round to four decimal places as needed.) (b) The area to the left of Z = 0.54 is (Round to four decimal places as needed.) (c) The area to the left of Z= -0.66 is. (Round to four decimal places as needed.) (d) The area to the left of Z= -0.27 is (Round to four decimal places as needed.)