Find the z-score for the value 82, when the mean is 98 and the standard deviation is 3. OA. 2= -567 OB. 2 -0.81 OC. z=0.81 OD. z= -5.33

In a population distribution, a score of X= 57 corresponds to z= -0.25 and a score of X= 87 corresponds to a z= 1.25. Find the mean and standard deviation for the population. Population mean=  Population standard deviation=

A distribution of values is normal with a mean of 202 and a standard deviation of 91.5.Find P75, which is the score separating the bottom 75% from the top 25%.P75 =

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 34 and the age of the winner for best actress was 50. For all best actors, the mean age is 46.9 years and the standard deviation is 6.9 years. For all best actresses, the mean age is 35.6 years and the standard deviation is 11.4 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z= the had the more extreme age. (Round to two decimal places.)

The average age of class is 22.3 years. The standard deviation is 4.7 years. If the variable is normally distributed, find the age that corresponds to the 94th percentile. SHOW WORK HOW YOU GOT THAT

Scores on an exam were normally distributed. Ten percent of the scores were below 60.0 and 80% were below 81. Find the mean and standard deviation of the scores. (Round the final answer for the mean to two decimal places.) (Round the final answer for the standard deviation to four decimal places.)

If a student scored 77 points on a test where the mean score was 84.5 and the standard deviation was 5.1. The student's z score is __________ a. -1.47 b. 16.57 c.  0.29 d. -0.29

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 33 and the age of the winner for best actress was 47. For all best actors, the mean age is 44.4 years and the standard deviation is 6.5 years. For all best actresses, the mean age is 32.8 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z = the V had the more extreme age. (Round to two decimal places.)

Scores on the SAT test have a mean of 1518 and a standard deviation of 325. Scores on the ACT test have a mean of 21.1 and a standard deviation of 4.8. Which of the following choices is not true? O A. An ACT Score of 17.0 has a z-score of -0.85. O B. An SAT score of 1490 has a z-score of -0.09. Oc. The ACT score of 17.0 is relatively better than the SAT score of 1490. O D. The SAT Score of 1490 is relatively better than the ACT score of 17.0.

A normal distribution has a mean of 85 and a standard deviation of 6. Find the z-score for a data value of 92. places Round to two decimal