Find the variance and standard deviation. Round the variance to two decimal places and standard deviation to at least three decimal places.

Finding the Mean, Variance, and Standard Deviation of a Binomial Distribution About 9% of the population has a particular genetic mutation. Suppose 100 people are randomly selected and the number with the particular genetic mutation are counted. Find the mean number of people who will have the genetic mutation in such groups of 100 people. Find the variance of the number of people who will have the genetic mutation in such groups of 100 people. Round answer to 2 decimal places. Find the standard deviation of number of people who will have the genetic mutation in such groups of 100 people. Round answer to 2 decimal places.

Solve the problem.Assume that mountain lions' weights are normally distributed with a mean of 62.6 kilograms and a standard deviation of 2.6 kilograms. If 70 mountain lions are randomly selected, find the probability that they have a mean weight between 61.9 kilograms and 62.8 pounds.

Internet Service Providers The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50 and the standard deviation is $20. The distribution is not Normal: many households pay a low rate as part of a bundle with phone or television service, but some pay much more for Internet only or for faster connections. A sample survey asks an SRS of 50 households with Internet access how much they pay. Let x be the mean amount paid. 1. Explain why you can't determine the probability that the amount a randomly selected household pays for access to the Internet exceeds $55. 2. What are the mean and standard deviation of the sampling distribution of x ? 3. What is the shape of the sampling distribution of x ? Justify your answer. 4. Find the probability that the average fee paid by the sample of households exceeds $55.