Find the values of x and y using pseudoinverse. x + 3y = 17; 5x + 7y = 19; 11x + 13y = 23
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Find the values of x and y using pseudoinverse.
x + 3y = 17; 5x + 7y = 19; 11x + 13y = 23
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- I am what you call a perfectionist. I always strive for perfection, and I appreciate everyone and everything that is perfect. That is why I have recently acquired an appreciation for perfect numbers! I absolutely need to know which numbers from 1 to 1000 are considered perfect. From what I recall, a perfect number is a positive integer that is equal to the sum of all its divisors other than itself. Example: 6 is a perfect number because the divisors of 6 other than itself are 1, 2, and 3, and 1 + 2 + 3 = 6. c++ codeQuestion4/ Combine the following two chromosomes using the PMX method to form two new children (cut points) (r1=2) and (r2=6) Suppose indicators start from zero Chromosome 1 6 4 5 7 8 9 2 3 1 Chromosome 2 1 2 3 4 5 6 7 9 m∞0 8the value of factor(P/F,i,10) can be found by getting the factor values for(P/F,i,4) and(P/f,i,6)and adding it to
- Starting with the first Fibonacci number, Fib(1) = 1, and the second Fibonacci number, Fib(2) = 1, what is the sum of Fib(8) and Fib(10)?There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 14.29%. A weighted average uses the percentages of each isotope to scale their contribution to the total mass. Each isotope's contribution is the percentage (in decimal form) multiplied by the mass of the isotope. What is the contribution (in amu) to the weighted average from the X-19 isotope, which has a mass of 19.00 amu?The square root of any number N>0 can be opproximated by repeated calculation using the formula N = squared_value NG = 0.5 (FG + N/FG) where NG stands for next guess and FG stands for first guess. The value of NG and FG are compared. If the two values are comparably close, then NG is the final answer. If the two values are off, NG becomes FG and the formula is used again to compute FG. After so many iterations, NG and FG will merge. a. Write a function that calculates the square root of a number using this method. The initial guess will be the starting value of FG (FG = 1). The function will compute a value for NG using the formula given and returns that value. (Change the name of the functions to something more meaningful) double fun_1 (double FG, double N); b. Write a function that prompts the user for any number N > 0, and returns that value back. The prototype is like follows: double fun_2 ( void ); c. Now inside the main function, check the difference between NG and FG to see…
- The square root of any number N>0 can be opproximated by repeated calculation using the formula N = squared_value NG = 0.5 (FG + N/FG) where NG stands for next guess and FG stands for first guess. The value of NG and FG are compared. If the two values are comparably close, then NG is the final answer. If the two values are off, NG becomes FG and the formula is used again to compute FG. After so many iterations, NG and FG will merge. a. Write a function that calculates the square root of a number using this method. The initial guess wilI be the starting value of FG (FG = 1). The function will compute a value for NG using the formula given and returns that value. (Change the name of the functions to something more meaningful) double fun_1 (double FG, double N); b. Write a function that prompts the user for any number N > 0, and returns that value back. The prototype is like follows: double fun_2 ( void ); Now inside the main function, check the difference between NG and FG to see whether…Find the digits X, Y and Z such that X09.YX16 = Z011.51g. Show all your work.You have to run Prim's algorithm for the problem defined by adjacency matrix: 1 2 3 4 5 6 7 8 9 1 0 10 9 999 999 17 999 999 999 2 3 69 10 0 14 4 2 999 999 13 999 14 0 7 999 999 999 999 999 4 999 4 7 0 999 2 8 999 999 5 999 2 999 999 0 6 999 1 999 6 17 999 999 2 6 0 999 7 999 7 999 999 999 8 999 999 0 11 4 8 999 13 999 999 1 7 11 9 999 999 999 999 999 999 4 80 8 0 1. We started from the vertex vl, so initially we have Y = {v1}: initial 1 2 3 4 5 6 7 8 9 nearest 1 1 1 1 1 1 1 1 1 distance -1 10 9 999 999 17 999 999 999 Print out the values stored in the nearest and distance arrays after first iteration of Prim's algorithm. Specify the value of vnear and the next vertex that has to be added to Y Hint: use (copy) the table above to record your answer.
- Q10: Using (ode45, ode23, or ode15s), solve the below dynamic electrical system differential equation. 1. The charge Q(t) on the capacitor in the electrical circuit shown satisfies the differential equation where d²Q dQ 1 +R- + √ √e dt2 dt L = 0.5 R = 6.0 C= 0.02 and V(t) is the applied voltage. V(t) = V(t), henrys is the coil's inductance ohms is the resistor's resistance farads is the capacitor's capacitance ellee (i) Is the circuit oscillatory? (ii) If V(t) = 24 sin(10r) volts and Q(0) = 0 = Q'(0), find Q(t). (iii) Sketch the transient solution, the steady state solution, and the full solution Q(t).TM M = (Q, E, I, 6, 90, 9a, qr), where Q = {90, 91, 92, 9a, 9r}, Σ = {0, 1}, r = {0, 1, L}, and 8 is: 8(qo, U) = (qr, U, R) 8(90, 0) = 8(go, 1) (91, 0, R) (qo, 1, R) = 8(g1, L) = (ga, U, R) 8(91,0) = (91, 0, R) 8(91, 1) = (92, 1, R) = (92, U, R) 8(92, U) 8(92, 0) = (90, 0, R) 8(92, 1) = (92, 1, R) i. Prove that M is NOT a decider. ii. Mathematically describe the language A that M recognises. Prove that A ≤ L(M). iii. Prove A = L(M). iv. Is A Turing-decidable? [Give clear reasons for your answer. No need for a formal proof.]sum= 0; for (int i = 0; i 1) { sum++; i= 1/2; } = 2*log2 (n) We denote by Ta(n), Tb (n), Te(n) the running time of the three fragments. 1. Give evaluations for Ta(n), Tb (n), Te(n). 2. Is T(n) = O(Ta(n)) ? Answer YES or NO and justify your answer. 3. Is Te(n) = (Ta(n)) ? Answer YES or NO and justify your answer.