Find the value of Z from the standard normal table such that the probability between Z and –Z is 0.8664.

If  z  is a standard normal variable, find the probability. P<−0.77<z2.25     0.8415     0.7671     0.7916     0.8264

If z is a standard normal variable, find the probability. P(z>0.57) O 0.3557 O 0.2843 O 0.2358 O 0.2514 の

Determine p(z>1.62) for a typical normal distribution. provide the probability in decimal form, rounded to four decimal points.

For the standard normal variable Z, find the probability P(Z>1.07)P(Z>1.07) : P(Z>1.07)=P(Z>1.07)= (Round the answer to 4 decimal places)

The mean height of women in a country​ (ages 20−​29) is 64.1 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 ​inches? Assume σ=2.58. The probability that the mean height for the sample is greater than 65 inches is

If z is a standard normal variable, find the probability. P(Z < 0.97) O 0.1660 0.8340 O 0.8078 0.8315