Find the value of the derivative (if it exists) at the indicated extremum. 4√6 (-4, 416) f(x) = - - 3x√x + 2 -2 10 5 сл -5 -10 2 4
Find the value of the derivative (if it exists) at the indicated extremum. 4√6 (-4, 416) f(x) = - - 3x√x + 2 -2 10 5 сл -5 -10 2 4
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.2: Derivatives Of Products And Quotients
Problem 35E
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Question
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![Step 2
Factor and simplify.
f'(x) =
= ²(x + 2)=¹/2 √x + 2(
-1/2
=
= ²³²(x + 2)-1¹/² (
-3(
2√x + 2
)
+ 4)
>]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c4d7c99-5f48-4c5b-a103-ebdb1d00bc36%2Fb5a0366c-ebd3-4f00-bd42-31006654ae09%2F8hupala_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Step 2
Factor and simplify.
f'(x) =
= ²(x + 2)=¹/2 √x + 2(
-1/2
=
= ²³²(x + 2)-1¹/² (
-3(
2√x + 2
)
+ 4)
>]
![Find the value of the derivative (if it exists) at the indicated extremum.
4√6
f(x) = - 3xVx + 2
-4
Step 2
Differentiate f(x) using the product rule.
f '(x) = – 3x 1/2
Factor and simplify.
10-
5
मैं
-5
-10
Step 1
The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval.
In the given problem, the extremum occurs when x = उ
The specified function is f (x) = −3x/x + 2 = −3x(x + 2) 1/2
2
0.5 ( x + 2)
4
-1
[2] +
+ (x + 2)1/2.
✓
-3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c4d7c99-5f48-4c5b-a103-ebdb1d00bc36%2Fb5a0366c-ebd3-4f00-bd42-31006654ae09%2Fzy8c5r9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the value of the derivative (if it exists) at the indicated extremum.
4√6
f(x) = - 3xVx + 2
-4
Step 2
Differentiate f(x) using the product rule.
f '(x) = – 3x 1/2
Factor and simplify.
10-
5
मैं
-5
-10
Step 1
The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval.
In the given problem, the extremum occurs when x = उ
The specified function is f (x) = −3x/x + 2 = −3x(x + 2) 1/2
2
0.5 ( x + 2)
4
-1
[2] +
+ (x + 2)1/2.
✓
-3)
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