Find the value of is(t)
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- Inductive Circuits Fill in all the missing values. Refer to the following formulas: XL=2fLL=XL2ff=XL2L Inductance (H) Frequency (Hz) Inductive Reactance ( ) 1.2 60 0.085 213.628 1000 4712.389 0.65 600 3.6 678.584 25 411.459 0.5 60 0.85 6408.849 20 201.062 0.45 400 4.8 2412.743 1000 40.841Find T 0.5 ms 40 92 www www 892 160 92 20 mH www444 mH b 720 mH 90 mH 60 mH 240 mH 20 mH (a) HE 80 nF 8 nF 10 nF 48 nF 20 nF b не (b)
- Electrical Engineering 6/0° v j1 N V1 V2 1Ω 1 Ω -j1 N= 2/0° A find loDiscussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 μF R Total 10+j0 Volts 10 Z0° 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°A 10 µF, a 15µF, and a 100µF capacitor are connected in parallel across 50V source. Determine the following: Total capacitance. Write the answer in µF G M k m Vμ K n Р 10⁹ 106 10³ 10-³ 10-6 10-⁹ 10-12 1 000 000 000 1 000 000 1 000 0,001 0,000001 0,000000001 0,000000000001
- By SUPERPOSITION, find io(t). 20 με 50 cos 2000r V 40 mH 2 sin 4000r Α 80 Ω 60 Ω 100 Ω +) 24 V+5V VDO EN Xtal 8ה 7 +5V Freq1 HGND | GND х Mhz Sensor0 crystal Freq26 5 Vss Out 04 PRE Xtal 1k Output HA7210IP 4 CLK CLR SN74HC7491 GND 0.01 μ GND +5V 4 +5V +5V +5V OE O/P3 0. 1µF | 47µF GND SG351P |2 x MHz GND GND Consider the Quartz Crystal Microbalance Sensor shown above, with crystal resonant frequency, x = 3.3 Mhz. You are given the following values: Active crystal area = 1.6 cm², and the change in frequency = - 10 Hz Calculate the change in mass, Am in nano gram, up to 2 decimal places. Answer:Circuits 1 HW 4 Q9
- Q5] find the current of the resistance 1892 if the value of the source is 7.4sin(100πt-44) volt HH 1mF R1 ww 18Q R4 •14Ω 3.9mF 13.100, 78.163⁰ mA O 14.100, 78.163⁰ mA O 15.100, 78.163⁰ mA 0.093H V15 mH 60 is = 50 Cos (314 t+30) A 1 mF Figure Q1(a)Useful constants: k=9.00×109 N.m2/C2 ε0= 8.85×10-12 C2/N.m2 µ0=4π×10-7 T.m/A mp=1.67×10-27 kg me=9.11×10-31 kg e=1.6×10-19 C g=10.0 m/s2