Find the surface area of the portion of the bowl z = 8+x² + y that lies below the plane z = 14.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.1: Parabolas
Problem 38E
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215 105005TI5
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Find the surface area of the portion of the bowl z = 8+x² + y² that lies below the plane z = 14.
Transcribed Image Text:y -2 1.5 -1 0.5 0 0.5 1 1.5 2 215 105005TI5 13 12 11 Z 10 Find the surface area of the portion of the bowl z = 8+x² + y² that lies below the plane z = 14.
Expert Solution
Step 1

Given,

z=8+x2+y2 ,z=14

Now substitute z=14 into the given surface for finding the intersection of the planes.

14=8+x2+y2x2+y2=6r2=6r=6

 

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