Find the solution to the recurrence relation by using an iterative approach. The recurrence relation a, = -5a, - 1 with the initial condition ao = 3 %3D

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Find the solution to the recurrence relation by using an iterative approach.
The recurrence relation a, = -5a, - 1 with the initial condition ao = 3
a. The solution for the recurrence relation is
an = -5a, - 1 = (-5)?a,-2 = - .. = (-5)"an - n = (-5)"ao = 3 - (-5)"
O b. The solution for the recurrence relation is
an = -5an - 1 = 5an - 2 =-
· = 5a, - n = 5a0 = 5(3) = 15
%3D
O c. The solution for the recurrence relation is
an = -5a, - 1 = (-5)²a, - 2 = · .
= (-5)"a, - n = (-5)°ao = 1.3 = 3
%3D
d. The solution for the recurrence relation is
an
= -5a, - 1 = -5an -2 = -
-5a, -
= -5a0 = -5(3) = 15
Transcribed Image Text:Find the solution to the recurrence relation by using an iterative approach. The recurrence relation a, = -5a, - 1 with the initial condition ao = 3 a. The solution for the recurrence relation is an = -5a, - 1 = (-5)?a,-2 = - .. = (-5)"an - n = (-5)"ao = 3 - (-5)" O b. The solution for the recurrence relation is an = -5an - 1 = 5an - 2 =- · = 5a, - n = 5a0 = 5(3) = 15 %3D O c. The solution for the recurrence relation is an = -5a, - 1 = (-5)²a, - 2 = · . = (-5)"a, - n = (-5)°ao = 1.3 = 3 %3D d. The solution for the recurrence relation is an = -5a, - 1 = -5an -2 = - -5a, - = -5a0 = -5(3) = 15
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