Find the solution to the characteristic equation you got in part (1). Use only the methods we taught in class (i.e., Do NOT solve the problem using Laplace / partial fractions). If both values of s are equal, write them twice. If they are not equal, write the larger one first (-15 is larger than -20). If they are complex, write the real part in the first box and the imaginary part in the second box. S₁= S₂= 1/sec 1/sec

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
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The circuit has a switch that closes at t=0. Resistor R = 2.6ohms. L=0.1H, C= 4F while Vs= 24 volts
Find the solution to the characteristic equation you got in part (i).
Use only the methods we taught in class (i.e., Do NOT solve the
problem using Laplace / partial fractions).
If both values of s are equal, write them twice. If they are not equal,
write the larger one first (-15 is larger than -20). If they are complex,
write the real part in the first box and the imaginary part in the
second box.
S₁=
S2
1/sec
1/sec
Transcribed Image Text:Find the solution to the characteristic equation you got in part (i). Use only the methods we taught in class (i.e., Do NOT solve the problem using Laplace / partial fractions). If both values of s are equal, write them twice. If they are not equal, write the larger one first (-15 is larger than -20). If they are complex, write the real part in the first box and the imaginary part in the second box. S₁= S2 1/sec 1/sec
(1)³a)
+
C
1
R
0=1
S
^(+
Transcribed Image Text:(1)³a) + C 1 R 0=1 S ^(+
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