Find the shaded area under the curve. X~Normal(u = 40, o2 = 16) %3D 0.9938 O 0.0062 O 0.4938 30

Use the table to find the area to the right of t = 1.717 with 22 degrees of freedom. Area to the right Degrees of Freedom 0.20 0.10 0.05 0.025 0.01 0.005 21 0.859 1.323 1.721 2.080 2.518 2.831 22 0.858 1.321 1.717 2.074 2.508 2.819 23 0.858 1.319 1.714 2.069 2.500 2.807 24 0.857 1.318 1.711 2.064 2.492 2.797 25 0.856 1.316 1.708 2.060 2.485 2.787 According to the table, the area to the right of t = 1.717 is Now find the area to the left of t = 1.717, rounding the result to two decimal places. (area to the left of t = 1.717) = 1 – (area to the right oft = 1.717) - = 1 -

Find the area of the shadal aren y=e X= In4

Find the indicated z-score shown in the graph to the right. Area = 0.2611 Z= ? 0 Z C e

Find the indicated z-score shown in the graph to the right. Area = 0.2266 z= ? 0 The z-score is (Round to two decimal places as needed.)