Find the resultant electric field created by the bars of 1 m length and 30 C charged at a point A at a distance of 8 and 4 m in the figure. Lines descending perpendicular to the bars from point A divide the bars in half. 4 m C 35° 30° 8m

Charge q, = 2.50 nC is at x, = 0 and charge q, = 6.00 nC is at x, = 4.00 m. At what point between the two charges is the electric field equal to zero? (Enter the x coordinate in m.) HINT Write an expression for the net electric field as a function of position, x, in the region between the two charges. (Don't forget that the electric field is a vector, so direction is important!) Set this expression equal to zero and solve for the variable x using the quadratic equation. Click the hint button again to remove this hint. m

A pair of unlike charges equal in magnitude and separated by a small distance is known as a dipole. Such a pair is situated on the x axis at equal distances from the origin as shown in the figure below. Use the direction rosette to answer the questions. ΧΑ 8 + * D E B 3 +q -9 5 9 zero magnitude (a) What is the direction of the net electric field at location C due to both charges? 5 X Did you consider the symmetry of the situation? What is the net contribution to the field from the y components of the field from each charge? (b) What is the direction of the net electric field at location D due to both charges? ---Select--- v (c) What is the direction of the net electric field at location E due to both charges? ---Select--- ✓ Additional Materials Reading 7

An electron in a uniform electric field experiences a force due east. If the electron is replaced with a proton, in which direction will it experience a force?   Question 3 options:   North   East   South   West